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| 1 | +using System; |
| 2 | +using Microsoft.VisualStudio.TestTools.UnitTesting; |
| 3 | + |
| 4 | +namespace LeetCodeProject |
| 5 | +{ |
| 6 | + [TestClass] |
| 7 | + public class AddTwoNumbersUnitTest |
| 8 | + { |
| 9 | + private ListNode listA; |
| 10 | + private ListNode listB; |
| 11 | + private ListNode listLongA; |
| 12 | + private ListNode listLongB; |
| 13 | + [TestInitialize] |
| 14 | + public void Initialize() |
| 15 | + { |
| 16 | + listA = new ListNode(2); |
| 17 | + listA.next = new ListNode(4); |
| 18 | + listA.next.next = new ListNode(3); |
| 19 | + listB = new ListNode(5); |
| 20 | + listB.next = new ListNode(6); |
| 21 | + listB.next.next = new ListNode(4); |
| 22 | + var arrayA = new int[61] { 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 9 }; |
| 23 | + listLongA = this.ArrayToListNode(arrayA); |
| 24 | + var arrayB = new int[61] { 5, 6, 4, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 2, 4, 3, 9, 9, 9, 9 }; |
| 25 | + listLongB = this.ArrayToListNode(arrayB); |
| 26 | + } |
| 27 | + |
| 28 | + private ListNode ArrayToListNode(int[] array) |
| 29 | + { |
| 30 | + ListNode result = null; |
| 31 | + ListNode lastNode = null; |
| 32 | + for (int i = 0; i < array.Length; i++) |
| 33 | + { |
| 34 | + var newNode = new ListNode(array[i]); |
| 35 | + if (result == null) |
| 36 | + { |
| 37 | + result = newNode; |
| 38 | + } |
| 39 | + else |
| 40 | + { |
| 41 | + lastNode.next = newNode; |
| 42 | + } |
| 43 | + lastNode = newNode; |
| 44 | + } |
| 45 | + return result; |
| 46 | + } |
| 47 | + |
| 48 | + [TestMethod] |
| 49 | + public void AddTwoNumbersTest() |
| 50 | + { |
| 51 | + //var result = AddTwoNumbers_MyErrorSolution(listA, listB); |
| 52 | + //var result = AddTwoNumbers_MyErrorSolution(listLongA, listLongB); |
| 53 | + |
| 54 | + var result = AddTwoNumbers_LeetCodeSolution(listLongA, listLongB); |
| 55 | + |
| 56 | + Assert.AreEqual(7, result.val); |
| 57 | + Assert.AreEqual(0, result.next.val); |
| 58 | + Assert.AreEqual(8, result.next.next.val); |
| 59 | + } |
| 60 | + |
| 61 | + /// <summary> |
| 62 | + /// My Solution |
| 63 | + /// </summary> |
| 64 | + private ListNode AddTwoNumbers_MySolution(ListNode l1, ListNode l2) |
| 65 | + { |
| 66 | + ListNode result = null; |
| 67 | + ListNode lastNode = null; |
| 68 | + int fact = 0; |
| 69 | + do |
| 70 | + { |
| 71 | + int v1 = l1 == null ? 0 : l1.val; |
| 72 | + int v2 = l2 == null ? 0 : l2.val; |
| 73 | + int sum = v1 + v2 + fact; |
| 74 | + int value = 0; |
| 75 | + if (sum >= 10) |
| 76 | + { |
| 77 | + fact = 1; |
| 78 | + value = sum - 10; |
| 79 | + } |
| 80 | + else |
| 81 | + { |
| 82 | + fact = 0; |
| 83 | + value = sum; |
| 84 | + } |
| 85 | + var newNode = new ListNode(value); |
| 86 | + if (result == null) |
| 87 | + { |
| 88 | + result = newNode; |
| 89 | + } |
| 90 | + else |
| 91 | + { |
| 92 | + lastNode.next = newNode; |
| 93 | + } |
| 94 | + lastNode = newNode; |
| 95 | + l1 = l1?.next; |
| 96 | + l2 = l2?.next; |
| 97 | + //参考LeetCode官方解法后发现,此判断可以移到While循环之外 |
| 98 | + if (l1 == null && l2 == null && fact > 0) |
| 99 | + { |
| 100 | + lastNode.next = new ListNode(fact); |
| 101 | + //或者可以直接break掉循环了 |
| 102 | + } |
| 103 | + } while (l1 != null || l2 != null); |
| 104 | + return result; |
| 105 | + } |
| 106 | + |
| 107 | + /// <summary> |
| 108 | + /// My Error Solution |
| 109 | + /// 这个方法是先将ListNode转换成数字然后相加,再将结果转换成ListNode |
| 110 | + /// 这个方法的问题就是没有考虑值类型的取值范围,在一些数字超大的情况下long也不能满足 |
| 111 | + /// </summary> |
| 112 | + private ListNode AddTwoNumbers_MyErrorSolution(ListNode l1, ListNode l2) |
| 113 | + { |
| 114 | + long num1 = ConvertToNumber(l1); |
| 115 | + long num2 = ConvertToNumber(l2); |
| 116 | + long sum = num1 + num2; |
| 117 | + ListNode result = null; |
| 118 | + ListNode lastNode = null; |
| 119 | + do |
| 120 | + { |
| 121 | + int value = Convert.ToInt32(sum < 10 ? sum : sum % 10); |
| 122 | + var newNode = new ListNode(value); |
| 123 | + if (result == null) |
| 124 | + { |
| 125 | + result = newNode; |
| 126 | + } |
| 127 | + else |
| 128 | + { |
| 129 | + lastNode.next = newNode; |
| 130 | + } |
| 131 | + lastNode = newNode; |
| 132 | + sum = sum / 10; |
| 133 | + |
| 134 | + } while (sum > 0); |
| 135 | + return result; |
| 136 | + } |
| 137 | + |
| 138 | + private long ConvertToNumber(ListNode listNode) |
| 139 | + { |
| 140 | + long result = listNode.val; |
| 141 | + long fact = 10; |
| 142 | + var next = listNode.next; |
| 143 | + while (next != null) |
| 144 | + { |
| 145 | + result = result + next.val * fact; |
| 146 | + fact = fact * 10; |
| 147 | + next = next.next; |
| 148 | + } |
| 149 | + return result; |
| 150 | + } |
| 151 | + |
| 152 | + /// <summary> |
| 153 | + /// LeetCode Solution |
| 154 | + /// </summary> |
| 155 | + private ListNode AddTwoNumbers_LeetCodeSolution(ListNode l1, ListNode l2) |
| 156 | + { |
| 157 | + ListNode dummyHead = new ListNode(0); |
| 158 | + ListNode p = l1, q = l2, curr = dummyHead; |
| 159 | + int carry = 0; |
| 160 | + while (p != null || q != null) |
| 161 | + { |
| 162 | + int x = (p != null) ? p.val : 0; |
| 163 | + int y = (q != null) ? q.val : 0; |
| 164 | + int sum = carry + x + y; |
| 165 | + carry = sum / 10; |
| 166 | + curr.next = new ListNode(sum % 10); |
| 167 | + curr = curr.next; |
| 168 | + if (p != null) p = p.next; |
| 169 | + if (q != null) q = q.next; |
| 170 | + } |
| 171 | + if (carry > 0) |
| 172 | + { |
| 173 | + curr.next = new ListNode(carry); |
| 174 | + } |
| 175 | + return dummyHead.next; |
| 176 | + } |
| 177 | + } |
| 178 | + |
| 179 | + |
| 180 | + public class ListNode |
| 181 | + { |
| 182 | + public int val; |
| 183 | + public ListNode next; |
| 184 | + public ListNode(int x) { val = x; } |
| 185 | + } |
| 186 | + |
| 187 | +} |
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