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Project Euler: Problem 6: Sum square difference

The sum of the squares of the first ten natural numbers is,

1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first n natural numbers and the square of the sum.