-
Notifications
You must be signed in to change notification settings - Fork 23
/
Copy path1048-longest-string-chain.js
44 lines (40 loc) · 1.35 KB
/
1048-longest-string-chain.js
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
/**
* 1048. Longest String Chain
* https://leetcode.com/problems/longest-string-chain/
* Difficulty: Medium
*
* You are given an array of words where each word consists of lowercase English letters.
*
* wordA is a predecessor of wordB if and only if we can insert exactly one letter anywhere in
* wordA without changing the order of the other characters to make it equal to wordB.
*
* For example, "abc" is a predecessor of "abac", while "cba" is not a predecessor of "bcad".
*
* A word chain is a sequence of words [word1, word2, ..., wordk] with k >= 1, where word1 is
* a predecessor of word2, word2 is a predecessor of word3, and so on. A single word is
* trivially a word chain with k == 1.
*
* Return the length of the longest possible word chain with words chosen from the given list
* of words.
*/
/**
* @param {string[]} words
* @return {number}
*/
var longestStrChain = function(words) {
const map = new Map();
let result = 1;
words.sort((a, b) => a.length - b.length);
for (const word of words) {
let currentLength = 1;
for (let i = 0; i < word.length; i++) {
const prev = word.slice(0, i) + word.slice(i + 1);
if (map.has(prev)) {
currentLength = Math.max(currentLength, map.get(prev) + 1);
}
}
map.set(word, currentLength);
result = Math.max(result, currentLength);
}
return result;
};