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Copy path1094.Car_Pooling.cpp
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1094.Car_Pooling.cpp
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/*
written by Pankaj Kumar.
country:-INDIA
Institute: National Institute of Technology, Uttarakhand
*/
typedef long long ll ;
typedef vector<int> vl;
typedef vector<vector<int>> vvl;
#define speed cin.tie(0);cout.tie(0);ios_base::sync_with_stdio(0);
/* Abbrevations */
#define ff first
#define ss second
#define mp make_pair
#define pb push_back
// loops
#define forin(arr,n) for(ll i=0;i<n;i++) cin>>arr[i];
// Some print
#define no cout<<"NO"<<endl;
#define yes cout<<"YES"<<endl;
// sort
#define all(V) (V).begin(),(V).end()
#define srt(V) sort(all(V))
#define srtGreat(V) sort(all(V),greater<ll>())
// some extra
#define printv(v) for(ll i=0;i<ll(v.size());i++){cout<<v[i]<<" ";} cout<<endl;
#define precision(x) cout<<fixed<<setprecision(x);
#define sz(V) ll(V.size())
/* ascii value
A=65,Z=90,a=97,z=122
*/
/* Some syntax
//Syntax to create a min heap for priority queue
//priority_queue <int, vector<int>, greater<int>>pq;
*/
ll ppow(ll n, ll m, ll mod){
if(m==0) return 1;
ll tmp=ppow(n, m/2, mod);
tmp=tmp*tmp%mod;
return m%2 ? tmp*n%mod: tmp;
}
namespace mod_operations{
ll modInv(ll n, ll mod){
return ppow(n,mod-2, mod);
}
ll modAdd(ll n, ll m, ll mod){
n=(n%mod+mod)%mod; m=(m%mod+mod)%mod;
return (n+m)%mod;
}
ll modMul(ll n, ll m, ll mod){
n=(n%mod+mod)%mod; m=(m%mod+mod)%mod;
return n*m %mod;
}
ll modSub(ll n, ll m, ll mod){
n=(n%mod+mod)%mod; m=(m%mod+mod)%mod;
return modAdd(n,-m, mod);
}
ll modDiv(ll n, ll m, ll mod){
return modMul(n, modInv(m, mod), mod);
}
}
using namespace mod_operations;
/* --------------------MAIN PROGRAM----------------------------*/
// to run ctrl+b
const ll INF=1e18;
const ll mod1=1e9+7;
const ll mod2=998244353;
// Techniques :
// divide into cases, brute force, pattern finding
// sort, greedy, binary search, two pointer
// transform into graph
// Experience :
// Cp is nothing but only observation and mathematics.
//Add main code here
class Solution {
public:
bool carPooling(vector<vector<int>>& trips, int capacity) {
vector<int> v(1001,0);
for(auto x:trips){
v[x[1]]+=x[0];
v[x[2]]-=x[0];
}
int current_capacity=0;
for(int i=0;i<=1000;i++){
current_capacity+=v[i];
if(current_capacity>capacity){
return false;
}
}
return true;
}
};
/* -----------------END OF PROGRAM --------------------*/
/*
* stuff you should look before submission
* constraint and time limit
* int overflow
* special test case (n=0||n=1||n=2)
* don't get stuck on one approach if you get wrong answer
*/