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If one has:
foo(u'.........' u'.........')
it gets converted to:
foo(six.u('........') six.u('........'))
that obviously does not work, better would be:
foo(six.u('.........' '.........'))
(moved from mitsuhiko/python-modernize#9 opened by @ThomasWaldmann)
The text was updated successfully, but these errors were encountered:
Test for #26 (wrong handling of multiple unicode literals); also incl…
d26e035
…udes the test for #19. refs #19, #26 Signed-off-by: Daira Hopwood <[email protected]>
9ade36c
d0d6397
The test looks correct now (i.e. it fails for the right reason).
Sorry, something went wrong.
daira
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If one has:
it gets converted to:
that obviously does not work, better would be:
(moved from mitsuhiko/python-modernize#9 opened by @ThomasWaldmann)
The text was updated successfully, but these errors were encountered: