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greedy_min_vertex_cover.py
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greedy_min_vertex_cover.py
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"""
* Author: Manuel Di Lullo (https://github.com/manueldilullo)
* Description: Approximization algorithm for minimum vertex cover problem.
Greedy Approach. Uses graphs represented with an adjacency list
URL: https://mathworld.wolfram.com/MinimumVertexCover.html
URL: https://cs.stackexchange.com/questions/129017/greedy-algorithm-for-vertex-cover
"""
import heapq
def greedy_min_vertex_cover(graph: dict) -> set[int]:
"""
Greedy APX Algorithm for min Vertex Cover
@input: graph (graph stored in an adjacency list where each vertex
is represented with an integer)
@example:
>>> graph = {0: [1, 3], 1: [0, 3], 2: [0, 3, 4], 3: [0, 1, 2], 4: [2, 3]}
>>> greedy_min_vertex_cover(graph)
{0, 1, 2, 4}
"""
# queue used to store nodes and their rank
queue: list[list] = []
# for each node and his adjacency list add them and the rank of the node to queue
# using heapq module the queue will be filled like a Priority Queue
# heapq works with a min priority queue, so I used -1*len(v) to build it
for key, value in graph.items():
# O(log(n))
heapq.heappush(queue, [-1 * len(value), (key, value)])
# chosen_vertices = set of chosen vertices
chosen_vertices = set()
# while queue isn't empty and there are still edges
# (queue[0][0] is the rank of the node with max rank)
while queue and queue[0][0] != 0:
# extract vertex with max rank from queue and add it to chosen_vertices
argmax = heapq.heappop(queue)[1][0]
chosen_vertices.add(argmax)
# Remove all arcs adjacent to argmax
for elem in queue:
# if v haven't adjacent node, skip
if elem[0] == 0:
continue
# if argmax is reachable from elem
# remove argmax from elem's adjacent list and update his rank
if argmax in elem[1][1]:
index = elem[1][1].index(argmax)
del elem[1][1][index]
elem[0] += 1
# re-order the queue
heapq.heapify(queue)
return chosen_vertices
if __name__ == "__main__":
import doctest
doctest.testmod()
graph = {0: [1, 3], 1: [0, 3], 2: [0, 3, 4], 3: [0, 1, 2], 4: [2, 3]}
print(f"Minimum vertex cover:\n{greedy_min_vertex_cover(graph)}")