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1614.MaximumNestingDepthoftheParentheses.py
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1614.MaximumNestingDepthoftheParentheses.py
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"""
A string is a valid parentheses string (denoted VPS) if it meets one of the
following:
- It is an empty string "", or a single character not equal to "(" or
")",
- It can be written as AB (A concatenated with B), where A and B are
VPS's, or
- It can be written as (A), where A is a VPS.
We can similarly define the nesting depth depth(S) of any VPS S as follows:
- depth("") = 0
- depth(C) = 0, where C is a string with a single character not equal
to "(" or ")".
- depth(A + B) = max(depth(A), depth(B)), where A and B are VPS's.
- depth("(" + A + ")") = 1 + depth(A), where A is a VPS.
For example, "", "()()", and "()(()())" are VPS's (with nesting depths 0,
1, and 2), and ")(" and "(()" are not VPS's.
Given a VPS represented as string s, return the nesting depth of s.
Example:
Input: s = "(1+(2*3)+((8)/4))+1"
Output: 3
Explanation: Digit 8 is inside of 3 nested parentheses in the string.
Example:
Input: s = "(1)+((2))+(((3)))"
Output: 3
Example:
Input: s = "1+(2*3)/(2-1)"
Output: 1
Example:
Input: s = "1"
Output: 0
Constraints:
- 1 <= s.length <= 100
- s consists of digits 0-9 and characters '+', '-', '*', '/', '(',
and ')'.
- It is guaranteed that parentheses expression s is a VPS.
"""
#Difficulty: Easy
#167 / 167 test cases passed.
#Runtime: 20 ms
#Memory Usage: 14.1 MB
#Runtime: 20 ms, faster than 99.08% of Python3 online submissions for Maximum Nesting Depth of the Parentheses.
#Memory Usage: 14.1 MB, less than 100.00% of Python3 online submissions for Maximum Nesting Depth of the Parentheses.
class Solution:
def maxDepth(self, s: str) -> int:
count = 0
depth = 0
for char in s:
if char == '(':
count += 1
if char == ')':
count -= 1
depth = max(depth, count)
return depth