From fd8138ca012d7092b20199bfc0c7717baf544123 Mon Sep 17 00:00:00 2001 From: Ulrik Buchholtz Date: Thu, 2 Jan 2025 15:18:57 +0000 Subject: [PATCH] update to 5.2.11 --- actions.tex | 21 ++++++++++----------- 1 file changed, 10 insertions(+), 11 deletions(-) diff --git a/actions.tex b/actions.tex index 476efb3..5c3011d 100644 --- a/actions.tex +++ b/actions.tex @@ -82,7 +82,7 @@ \section{Group actions ($G$-sets)} with \emph{underlying type} $X(\sh_G)$. More generally, an action of $G$ on an element of type $A$ is a function $X : \BG\to A$, see~\cref{sec:actions} below.} - + \begin{example}\label{def:trivGset} If $G$ is a group and $X$ is a set, then $\triv_G X$ defined by \[\triv_G X(z)\defequi X, \quad\text{for all $z:\BG$,}\] @@ -217,7 +217,7 @@ \section{Group actions ($G$-sets)} then a \emph{map from $X$ to $Y$} is an element of the type \[ - \prod_{z:\BG}(X(z)\to Y(z)). + \Hom_G(X,Y) \defeq \prod_{z:\BG}(X(z)\to Y(z)). \] When $f$ is such a map, we may write $f_z$ for $f(z)$. \index{map!of $G$-sets}\index{$G$-subset} @@ -243,12 +243,12 @@ \section{Group actions ($G$-sets)} \begin{definition}\label{def:Gsubset} A \emph{$G$-predicate of $X$} is a map from $X$ to the $G$-set that is - constant $\Prop$. The type of all such maps is denoted by + constant $\Prop$. The type of all such maps is denoted by% + \glossary(SubGX){$\protect\Sub_G(X)$}{set of $G$-subsets of $X$} \[ - \Sub_{G,X}\defeq \prod_{z:\BG}(X(z)\to\Prop). + \Sub_G(X)\defeq \Hom_G(X,\triv_G\Prop) \jdeq \prod_{z:\BG}(X(z)\to\Prop). \] - %\glossary(Gsubsets){\protect{$\Sub_{G,X}$}}{set of $G$-subsets of $X$} ERROR - Similarly to \cref{cor:subtype-same-level}, $\Sub_{G,X}$ is a set. + Similarly to \cref{cor:subtype-same-level}, $\Sub_{G}(X)$ is a set. If $P$ is a $G$-subset of $X$, then the \emph{underlying $G$-set of $P$}, denoted by $X_P$, is defined by \[ @@ -258,13 +258,12 @@ \section{Group actions ($G$-sets)} \end{definition} \begin{xca}\label{xca:SubGX-closedSubXshG} -\MB{MB unsure this was what UB meant.} -Show that evaluation at $\sh_G$ is an equivalence from $\Sub_{G,X}$ to +Show that evaluation at $\sh_G$ is an equivalence from $\Sub_G(X)$ to \[ -\sum_{Q:X(\sh_G)\to\Prop} + \sum_{Q:\Sub(X(\sh_G))} \prod_{x:X(\sh_G)} - \bigl(Q(x)\to\prod_{g:\USymG} Q(g\cdot x)\bigr). -\] + \Bigl(Q(x)\to\prod_{g:\USymG} Q(g\cdot x)\Bigr). +\] The latter type is the type of all subsets of $X(\sh_G)$ that are closed under the group action. \end{xca}