forked from edorado93/leetcode
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path_336_PalindromePairs.java
71 lines (68 loc) · 2.02 KB
/
_336_PalindromePairs.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
package hashTable;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
/**
*
* Problem:
*
* Given a list of unique words, find all pairs of distinct indices (i, j) in
* the given list, so that the concatenation of the two words, i.e. words[i] +
* words[j] is a palindrome.
*
* Example 1: Given words = ["bat", "tab", "cat"] Return [[0, 1], [1, 0]] The
* palindromes are ["battab", "tabbat"]
*
* Example 2: Given words = ["abcd", "dcba", "lls", "s", "sssll"] Return [[0,
* 1], [1, 0], [3, 2], [2, 4]] The palindromes are ["dcbaabcd", "abcddcba",
* "slls", "llssssll"]
*
* Solution: HashMap, key: String, value: index
*
*/
public class _336_PalindromePairs {
public List<List<Integer>> palindromePairs(String[] words) {
List<List<Integer>> res = new ArrayList<>();
Map<String, Integer> map = new HashMap<>();
for (int i = 0; i < words.length; i++) {
map.put(words[i], i);
}
for (int i = 0; i < words.length; i++) {
for (int j = 0; j <= words[i].length(); j++) {
String left = words[i].substring(0, j);
String right = words[i].substring(j);
if (isPalindrome(left)) {
String rightReverse = new StringBuilder(right).reverse().toString();
if (map.containsKey(rightReverse) && map.get(rightReverse) != i) {
List<Integer> list = new ArrayList<>();
list.add(map.get(rightReverse));
list.add(i);
res.add(list);
}
}
if (isPalindrome(right)) {
String leftReverse = new StringBuilder(left).reverse().toString();
// duplicate abcd, dcba right.length() != 0
if (map.containsKey(leftReverse) && map.get(leftReverse) != i && right.length() != 0) {
List<Integer> list = new ArrayList<>();
list.add(i);
list.add(map.get(leftReverse));
res.add(list);
}
}
}
}
return res;
}
private boolean isPalindrome(String s) {
int left = 0;
int right = s.length() - 1;
while (left <= right) {
if (s.charAt(left++) != s.charAt(right--)) {
return false;
}
}
return true;
}
}