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test_connection.py
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from fixtures import * # noqa: F401,F403
from fixtures import TEST_NETWORK
from flaky import flaky # noqa: F401
from ephemeral_port_reserve import reserve # type: ignore
from pyln.client import RpcError, Millisatoshi
import pyln.proto.wire as wire
from utils import (
only_one, wait_for, sync_blockheight, TIMEOUT,
expected_peer_features, expected_node_features,
expected_channel_features,
check_coin_moves, first_channel_id, account_balance, basic_fee,
scriptpubkey_addr,
DEVELOPER, EXPERIMENTAL_FEATURES, mine_funding_to_announce
)
from pyln.testing.utils import SLOW_MACHINE, VALGRIND, EXPERIMENTAL_DUAL_FUND, FUNDAMOUNT
import os
import pytest
import random
import re
import time
import unittest
import websocket
def test_connect_basic(node_factory):
l1, l2 = node_factory.line_graph(2, fundchannel=False)
# These should be in openingd.
assert l1.rpc.getpeer(l2.info['id'])['connected']
assert l2.rpc.getpeer(l1.info['id'])['connected']
assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0
assert len(l2.rpc.getpeer(l1.info['id'])['channels']) == 0
# Reconnect should be a noop
ret = l1.rpc.connect(l2.info['id'], 'localhost', port=l2.port)
assert ret['id'] == l2.info['id']
assert ret['address'] == {'type': 'ipv4', 'address': '127.0.0.1', 'port': l2.port}
ret = l2.rpc.connect(l1.info['id'], host='localhost', port=l1.port)
assert ret['id'] == l1.info['id']
# FIXME: This gives a bogus address (since they connected to us): better to give none!
assert 'address' in ret
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
if DEVELOPER:
print(l1.daemon.wait_for_log("Peer says it sees our address as: 127.0.0.1:[0-9]{5}"))
# Should get reasonable error if unknown addr for peer.
with pytest.raises(RpcError, match=r'Unable to connect, no address known'):
l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e')
# Should get reasonable error if connection refuse.
with pytest.raises(RpcError, match=r'Connection establishment: Connection refused'):
l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', 1)
# Should get reasonable error if wrong key for peer.
with pytest.raises(RpcError, match=r'Cryptographic handshake: peer closed connection \(wrong key\?\)'):
l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', l2.port)
@pytest.mark.developer("needs DEVELOPER=1 for having localhost remote_addr and fast gossip")
def test_remote_addr(node_factory, bitcoind):
"""Check address discovery (BOLT1 #917) init remote_addr works as designed:
`node_announcement` update must only be send out when:
- at least two peers
- we have a channel with
- report the same `remote_addr`
"""
# don't announce anything per se
opts = {'announce-addr': [], 'may_reconnect': True}
l1, l2, l3 = node_factory.get_nodes(3, opts=opts)
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
l2.daemon.wait_for_log("Peer says it sees our address as: 127.0.0.1:[0-9]{5}")
# Fund first channel so initial node_announcement is send
l1.fundchannel(l2)
bitcoind.generate_block(5)
l1.daemon.wait_for_log(f"Received node_announcement for node {l2.info['id']}")
# when we restart l1 with a channel and reconnect, node_annoucement update
# must not yet be send as we need the same `remote_addr` confirmed from a
# another peer we have a channel with.
# Note: In this state l2 stores remote_addr as reported by l1
assert not l2.daemon.is_in_log("Update our node_announcement for discovered address: 127.0.0.1:9735")
l1.restart()
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
l2.daemon.wait_for_log("Peer says it sees our address as: 127.0.0.1:[0-9]{5}")
# now only l1 sees l2 without announced addresses (disabled by opts)
assert(len(l1.rpc.listnodes(l2.info['id'])['nodes'][0]['addresses']) == 0)
assert(len(l3.rpc.listnodes(l2.info['id'])['nodes']) == 0)
assert not l2.daemon.is_in_log("Update our node_announcement for discovered address: 127.0.0.1:9735")
# connect second node. This will not yet trigger `node_annoucement` update,
# as we again do not have a channel at the time we connected.
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
l2.daemon.wait_for_log("Peer says it sees our address as: 127.0.0.1:[0-9]{5}")
# fund channel and check we didn't send Update earlier already
l2.fundchannel(l3, wait_for_active=True)
bitcoind.generate_block(5)
assert not l2.daemon.is_in_log("Update our node_announcement for discovered address: 127.0.0.1:9735")
# restart, reconnect and re-check for updated node_annoucement. This time
# l2 sees that two different peers with channel reported the same `remote_addr`.
l3.restart()
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
l2.daemon.wait_for_log("Peer says it sees our address as: 127.0.0.1:[0-9]{5}")
l2.daemon.wait_for_log("Update our node_announcement for discovered address: 127.0.0.1:9735")
l1.daemon.wait_for_log(f"Received node_announcement for node {l2.info['id']}")
address = l1.rpc.listnodes(l2.info['id'])['nodes'][0]['addresses'][0]
assert address['type'] == "ipv4"
assert address['address'] == "127.0.0.1"
assert address['port'] == 9735
@pytest.mark.developer("needs DEVELOPER=1 for having localhost remote_addr and fast gossip")
def test_remote_addr_disabled(node_factory, bitcoind):
"""Simply tests that IP address discovery annoucements can be turned off
"""
opts = {'announce-addr': [], 'disable-ip-discovery': None, 'may_reconnect': True}
l1, l2, l3 = node_factory.get_nodes(3, opts=opts)
# l1->l2
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
l2.daemon.wait_for_log("Peer says it sees our address as: 127.0.0.1:[0-9]{5}")
l1.fundchannel(l2)
bitcoind.generate_block(5)
l1.daemon.wait_for_log(f"Received node_announcement for node {l2.info['id']}")
# l2->l3
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
l2.daemon.wait_for_log("Peer says it sees our address as: 127.0.0.1:[0-9]{5}")
l2.fundchannel(l3)
bitcoind.generate_block(5)
# restart both and wait for channels to be ready
l1.restart()
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
l2.daemon.wait_for_log("Already have funding locked in")
l3.restart()
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
l2.daemon.wait_for_log("Already have funding locked in")
# if ip discovery would have been enabled, we would have send an updated
# node_annoucement by now. Check we didn't...
assert not l2.daemon.is_in_log("Update our node_announcement for discovered address")
def test_connect_standard_addr(node_factory):
"""Test standard node@host:port address
"""
l1, l2, l3 = node_factory.get_nodes(3)
# node@host
ret = l1.rpc.connect("{}@{}".format(l2.info['id'], 'localhost'), port=l2.port)
assert ret['id'] == l2.info['id']
assert ret['address'] == {'type': 'ipv4', 'address': '127.0.0.1', 'port': l2.port}
# node@host:port
ret = l1.rpc.connect("{}@localhost:{}".format(l3.info['id'], l3.port))
assert ret['id'] == l3.info['id']
# node@[ipv6]:port --- not supported by our CI
# ret = l1.rpc.connect("{}@[::1]:{}".format(l3.info['id'], l3.port))
# assert ret['id'] == l3.info['id']
def test_reconnect_channel_peers(node_factory, executor):
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundchannel(l2, 10**6)
l2.restart()
# Should reconnect.
wait_for(lambda: only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
wait_for(lambda: only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected'])
# Connect command should succeed.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Stop l2 and wait for l1 to notice.
l2.stop()
wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
# Now should fail.
with pytest.raises(RpcError, match=r'(Connection refused|Bad file descriptor)'):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Wait for exponential backoff to give us a 2 second window.
l1.daemon.wait_for_log('Will try reconnect in 2 seconds')
# It should now succeed when it restarts.
l2.start()
# Multiples should be fine!
fut1 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
fut2 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
fut3 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
fut1.result(10)
fut2.result(10)
fut3.result(10)
def test_connection_moved(node_factory, executor):
slow_start = os.path.join(os.getcwd(), 'tests/plugins/slow_start.py')
options = {'may_reconnect': True, 'plugin': slow_start}
l1, l2 = node_factory.get_nodes(2, opts=options)
# Set up the plugin to wait for a connection
executor.submit(l1.rpc.waitconn)
log = l1.daemon.wait_for_log('listening for connections')
match = re.search(r'on port (\d*)', log)
assert match and len(match.groups()) == 1
hang_port = int(match.groups()[0])
# Attempt connection
fut_hang = executor.submit(l1.rpc.connect, l2.info['id'],
'localhost', hang_port)
l1.daemon.wait_for_log('connection from')
# Provide correct connection details
ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
assert ret['address'] == {'type': 'ipv4', 'address': '127.0.0.1', 'port': l2.port}
# If we failed to update the connection, this call will error
fut_hang.result(TIMEOUT)
def test_balance(node_factory):
l1, l2 = node_factory.line_graph(2, fundchannel=True)
p1 = only_one(l1.rpc.getpeer(peer_id=l2.info['id'], level='info')['channels'])
p2 = only_one(l2.rpc.getpeer(l1.info['id'], 'info')['channels'])
assert p1['msatoshi_to_us'] == 10**6 * 1000
assert p1['msatoshi_total'] == 10**6 * 1000
assert p2['msatoshi_to_us'] == 0
assert p2['msatoshi_total'] == 10**6 * 1000
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_bad_opening(node_factory):
# l1 asks for a too-long locktime
l1 = node_factory.get_node(options={'watchtime-blocks': 100})
l2 = node_factory.get_node(options={'max-locktime-blocks': 99})
ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
assert ret['id'] == l2.info['id']
l1.daemon.wait_for_log('Handed peer, entering loop')
l2.daemon.wait_for_log('Handed peer, entering loop')
l1.fundwallet(10**6 + 1000000)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 10**6)
l2.daemon.wait_for_log('to_self_delay 100 larger than 99')
@pytest.mark.developer("gossip without DEVELOPER=1 is slow")
@unittest.skipIf(TEST_NETWORK != 'regtest', "Fee computation and limits are network specific")
@pytest.mark.slow_test
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_opening_tiny_channel(node_factory):
# Test custom min-capacity-sat parameters
#
# [l1]-----> [l2] (~6000) - technical minimal value that wont be rejected
# \
# o---> [l3] (10000) - the current default
# \
# o-> [l4] (20000) - a node with a higher minimal value
#
# For each:
# 1. Try to establish channel with capacity 1sat smaller than min_capacity_sat
# 2. Try to establish channel with capacity exact min_capacity_sat
#
# BOLT2
# The receiving node MAY fail the channel if:
# - funding_satoshis is too small
# - it considers `feerate_per_kw` too small for timely processing or unreasonably large.
#
dustlimit = 546
reserves = 2 * dustlimit
min_commit_tx_fees = basic_fee(7500)
overhead = reserves + min_commit_tx_fees
if EXPERIMENTAL_FEATURES or EXPERIMENTAL_DUAL_FUND:
# Gotta fund those anchors too!
overhead += 660
l2_min_capacity = 1 # just enough to get past capacity filter
l3_min_capacity = 10000 # the current default
l4_min_capacity = 20000 # a server with more than default minimum
opts = [{'min-capacity-sat': 0},
{'min-capacity-sat': l2_min_capacity},
{'min-capacity-sat': l3_min_capacity},
{'min-capacity-sat': l4_min_capacity}]
l1, l2, l3, l4 = node_factory.get_nodes(4, opts=opts)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
l1.rpc.connect(l4.info['id'], 'localhost', l4.port)
with pytest.raises(RpcError, match=r'They sent [error|warning].*channel capacity is .*, which is below .*sat'):
l1.fundchannel(l2, l2_min_capacity + overhead - 1)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundchannel(l2, l2_min_capacity + overhead)
with pytest.raises(RpcError, match=r'They sent [error|warning].*channel capacity is .*, which is below .*sat'):
l1.fundchannel(l3, l3_min_capacity + overhead - 1)
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
l1.fundchannel(l3, l3_min_capacity + overhead)
with pytest.raises(RpcError, match=r'They sent [error|warning].*channel capacity is .*, which is below .*sat'):
l1.fundchannel(l4, l4_min_capacity + overhead - 1)
l1.rpc.connect(l4.info['id'], 'localhost', l4.port)
l1.fundchannel(l4, l4_min_capacity + overhead)
# Note that this check applies locally too, so you can't open it if
# you would reject it.
l3.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError, match=r"channel capacity is .*, which is below .*sat"):
l3.fundchannel(l2, l3_min_capacity + overhead - 1)
l3.rpc.connect(l2.info['id'], 'localhost', l2.port)
l3.fundchannel(l2, l3_min_capacity + overhead)
def test_second_channel(node_factory):
l1, l2, l3 = node_factory.get_nodes(3)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
l1.fundchannel(l2, 10**6)
l1.fundchannel(l3, 10**6)
def test_channel_abandon(node_factory, bitcoind):
"""Our open tx isn't mined, we doublespend it away"""
l1, l2 = node_factory.get_nodes(2)
SATS = 10**6
# Add some for fees
l1.fundwallet(SATS + 10000)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], SATS, feerate='1875perkw')
opening_utxo = only_one([o for o in l1.rpc.listfunds()['outputs'] if o['reserved']])
psbt = l1.rpc.utxopsbt(0, "253perkw", 0, [opening_utxo['txid'] + ':' + str(opening_utxo['output'])], reserve=0, reservedok=True)['psbt']
# We expect a reservation for 2016 blocks; unreserve it.
reservations = only_one(l1.rpc.unreserveinputs(psbt, reserve=2015)['reservations'])
assert reservations['reserved']
assert reservations['reserved_to_block'] == bitcoind.rpc.getblockchaininfo()['blocks'] + 1
assert only_one(l1.rpc.unreserveinputs(psbt, reserve=1)['reservations'])['reserved'] is False
# Now it's unreserved, we can doublespend it (as long as we exceed
# previous fee to RBF!).
withdraw = l1.rpc.withdraw(l1.rpc.newaddr()['bech32'], "all")
assert bitcoind.rpc.decoderawtransaction(withdraw['tx'])['vout'][0]['value'] > SATS / 10**8
bitcoind.generate_block(1, wait_for_mempool=withdraw['txid'])
# FIXME: lightningd should notice channel will never now open!
print(l1.rpc.listpeers())
assert (only_one(only_one(l1.rpc.listpeers()['peers'])['channels'])['state']
== 'CHANNELD_AWAITING_LOCKIN')
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_disconnect(node_factory):
# These should all make us fail
disconnects = ['-WIRE_INIT',
'+WIRE_INIT']
l1 = node_factory.get_node(disconnect=disconnects)
l2 = node_factory.get_node()
with pytest.raises(RpcError):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Should have 3 connect fails.
for d in disconnects:
l1.daemon.wait_for_log('{}-.*Failed connected out'
.format(l2.info['id']))
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_disconnect_opener(node_factory):
# Now error on opener side during channel open.
disconnects = ['-WIRE_OPEN_CHANNEL',
'+WIRE_OPEN_CHANNEL',
'-WIRE_FUNDING_CREATED']
if EXPERIMENTAL_DUAL_FUND:
disconnects = ['-WIRE_OPEN_CHANNEL2',
'+WIRE_OPEN_CHANNEL2',
'-WIRE_TX_ADD_INPUT',
'+WIRE_TX_ADD_INPUT',
'-WIRE_TX_ADD_OUTPUT',
'+WIRE_TX_ADD_OUTPUT',
'-WIRE_TX_COMPLETE',
'+WIRE_TX_COMPLETE']
l1 = node_factory.get_node(disconnect=disconnects)
l2 = node_factory.get_node(may_reconnect=EXPERIMENTAL_DUAL_FUND)
l1.fundwallet(2000000)
for d in disconnects:
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 25000)
assert l1.rpc.getpeer(l2.info['id']) is None
# This one will succeed.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 25000)
# Should still only have one peer!
assert len(l1.rpc.listpeers()['peers']) == 1
assert len(l2.rpc.listpeers()['peers']) == 1
def test_remote_disconnect(node_factory):
l1, l2 = node_factory.get_nodes(2)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
wait_for(lambda: l2.rpc.listpeers()['peers'] != [])
l2.rpc.disconnect(l1.info['id'])
# l1 should notice!
wait_for(lambda: l1.rpc.listpeers()['peers'] == [])
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_disconnect_fundee(node_factory):
# Now error on fundee side during channel open.
disconnects = ['-WIRE_ACCEPT_CHANNEL',
'+WIRE_ACCEPT_CHANNEL']
if EXPERIMENTAL_DUAL_FUND:
disconnects = ['-WIRE_ACCEPT_CHANNEL2',
'+WIRE_ACCEPT_CHANNEL2',
'-WIRE_TX_COMPLETE',
'+WIRE_TX_COMPLETE']
l1 = node_factory.get_node()
l2 = node_factory.get_node(disconnect=disconnects)
l1.fundwallet(2000000)
for d in disconnects:
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 25000)
assert l1.rpc.getpeer(l2.info['id']) is None
# This one will succeed.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 25000)
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
@unittest.skipIf(TEST_NETWORK != 'regtest', 'elementsd doesnt yet support PSBT features we need')
@pytest.mark.developer
@pytest.mark.openchannel('v2')
def test_disconnect_fundee_v2(node_factory):
# Now error on fundee side during channel open, with them funding
disconnects = ['-WIRE_ACCEPT_CHANNEL2',
'+WIRE_ACCEPT_CHANNEL2',
'-WIRE_TX_ADD_INPUT',
'+WIRE_TX_ADD_INPUT',
'-WIRE_TX_ADD_OUTPUT',
'+WIRE_TX_ADD_OUTPUT',
'-WIRE_TX_COMPLETE',
'+WIRE_TX_COMPLETE']
l1 = node_factory.get_node()
l2 = node_factory.get_node(disconnect=disconnects,
options={'funder-policy': 'match',
'funder-policy-mod': 100,
'funder-fuzz-percent': 0,
'funder-lease-requests-only': False})
l1.fundwallet(2000000)
l2.fundwallet(2000000)
for d in disconnects:
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 25000)
assert l1.rpc.getpeer(l2.info['id']) is None
# This one will succeed.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 25000)
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_disconnect_half_signed(node_factory):
# Now, these are the corner cases. Fundee sends funding_signed,
# but opener doesn't receive it.
disconnects = ['-WIRE_FUNDING_SIGNED']
if EXPERIMENTAL_DUAL_FUND:
disconnects = ['-WIRE_COMMITMENT_SIGNED']
l1 = node_factory.get_node()
l2 = node_factory.get_node(disconnect=disconnects)
l1.fundwallet(2000000)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 25000)
# Peer remembers, opener doesn't.
assert l1.rpc.getpeer(l2.info['id']) is None
assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id']
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_reconnect_signed(node_factory):
# This will fail *after* both sides consider channel opening.
disconnects = ['+WIRE_FUNDING_SIGNED']
if EXPERIMENTAL_DUAL_FUND:
disconnects = ['+WIRE_COMMITMENT_SIGNED']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.fundwallet(2000000)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 25000)
# They haven't forgotten each other.
assert l1.rpc.getpeer(l2.info['id'])['id'] == l2.info['id']
assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id']
# Technically, this is async to fundchannel (and could reconnect first)
if EXPERIMENTAL_DUAL_FUND:
l1.daemon.wait_for_logs(['sendrawtx exit 0',
'Peer has reconnected, state DUALOPEND_OPEN_INIT'])
else:
l1.daemon.wait_for_logs(['sendrawtx exit 0',
'Peer has reconnected, state CHANNELD_AWAITING_LOCKIN'])
l1.bitcoin.generate_block(6)
l1.daemon.wait_for_log(' to CHANNELD_NORMAL')
l2.daemon.wait_for_log(' to CHANNELD_NORMAL')
@pytest.mark.skip('needs blackhold support')
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_reconnect_openingd(node_factory):
# Openingd thinks we're still opening; opener reconnects..
disconnects = ['0WIRE_ACCEPT_CHANNEL']
if EXPERIMENTAL_DUAL_FUND:
disconnects = ['0WIRE_ACCEPT_CHANNEL2']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundwallet(2000000)
# l2 closes on l1, l1 forgets.
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 25000)
assert l1.rpc.getpeer(l2.info['id']) is None
# Reconnect.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# We should get a message about reconnecting.
l2.daemon.wait_for_log('Killing opening daemon: Reconnected')
l2.daemon.wait_for_log('Handed peer, entering loop')
# Should work fine.
l1.rpc.fundchannel(l2.info['id'], 25000)
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.bitcoin.generate_block(3)
# Just to be sure, second openingd hand over to channeld. This log line is about channeld being started
l2.daemon.wait_for_log(r'channeld-chan#[0-9]: pid [0-9]+, msgfd [0-9]+')
@pytest.mark.skip('needs blackhold support')
@pytest.mark.developer
def test_reconnect_gossiping(node_factory):
# connectd thinks we're still gossiping; peer reconnects.
disconnects = ['0INVALID 33333']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Make sure l2 knows about l1
wait_for(lambda: l2.rpc.listpeers(l1.info['id'])['peers'] != [])
l2.rpc.sendcustommsg(l1.info['id'], bytes([0x82, 0x35]).hex())
wait_for(lambda: l1.rpc.listpeers(l2.info['id'])['peers'] == [])
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l2.daemon.wait_for_log('processing now old peer gone')
@flaky
@pytest.mark.developer("needs dev-disconnect")
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_reconnect_no_update(node_factory, executor, bitcoind):
"""Test that funding_locked is retransmitted on reconnect if new channel
This tests if the `funding_locked` is sent if we receive a
`channel_reestablish` message with `next_commitment_number` == 1
and our `next_commitment_number` == 1.
This test makes extensive use of disconnects followed by automatic
reconnects. See comments for details.
"""
disconnects = ["-WIRE_FUNDING_LOCKED", "-WIRE_SHUTDOWN"]
# Allow bad gossip because it might receive WIRE_CHANNEL_UPDATE before
# announcement of the disconnection
l1 = node_factory.get_node(may_reconnect=True, allow_bad_gossip=True)
l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True)
# For channeld reconnection
l1.rpc.connect(l2.info["id"], "localhost", l2.port)
# LightningNode.fundchannel will fund the channel and generate a
# block. The block triggers the funding_locked message, which
# causes a disconnect. The retransmission is then caused by the
# automatic retry.
fundchannel_exec = executor.submit(l1.fundchannel, l2, 10**6, False)
if l1.config('experimental-dual-fund'):
l1.daemon.wait_for_log(r"dualopend.* Retransmitting funding_locked for channel")
else:
l1.daemon.wait_for_log(r"channeld.* Retransmitting funding_locked for channel")
sync_blockheight(bitcoind, [l1, l2])
fundchannel_exec.result()
l1.stop()
# For closingd reconnection
l1.daemon.start()
# Close will trigger the -WIRE_SHUTDOWN and we then wait for the
# automatic reconnection to trigger the retransmission.
l1.rpc.close(l2.info['id'], 0)
l2.daemon.wait_for_log(r"channeld.* Retransmitting funding_locked for channel")
l1.daemon.wait_for_log(r"CLOSINGD_COMPLETE")
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_reconnect_normal(node_factory):
# Should reconnect fine even if locked message gets lost.
disconnects = ['-WIRE_FUNDING_LOCKED',
'+WIRE_FUNDING_LOCKED']
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundchannel(l2, 10**6)
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_reconnect_sender_add1(node_factory):
# Fail after add is OK, will cause payment failure though.
# Make sure it doesn't send commit before it sees disconnect though.
disconnects = ['-WIRE_UPDATE_ADD_HTLC',
'+WIRE_UPDATE_ADD_HTLC']
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True,
options={'commit-time': 2000},
feerates=(7500, 7500, 7500, 7500))
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundchannel(l2, 10**6)
amt = 200000000
inv = l2.rpc.invoice(amt, 'test_reconnect_sender_add1', 'desc')
rhash = inv['payment_hash']
assert only_one(l2.rpc.listinvoices('test_reconnect_sender_add1')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
for i in range(0, len(disconnects)):
with pytest.raises(RpcError):
l1.rpc.sendpay(route, rhash, payment_secret=inv['payment_secret'])
l1.rpc.waitsendpay(rhash)
# Wait for reconnection.
l1.daemon.wait_for_log('Already have funding locked in')
# This will send commit, so will reconnect as required.
l1.rpc.sendpay(route, rhash, payment_secret=inv['payment_secret'])
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_reconnect_sender_add(node_factory):
disconnects = ['-WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
if EXPERIMENTAL_DUAL_FUND:
disconnects = ['=WIRE_COMMITMENT_SIGNED'] + disconnects
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True,
feerates=(7500, 7500, 7500, 7500))
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundchannel(l2, 10**6)
amt = 200000000
inv = l2.rpc.invoice(amt, 'testpayment', 'desc')
rhash = inv['payment_hash']
assert only_one(l2.rpc.listinvoices('testpayment')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
# This will send commit, so will reconnect as required.
l1.rpc.sendpay(route, rhash, payment_secret=inv['payment_secret'])
# Should have printed this for every reconnect.
for i in range(0, len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_reconnect_receiver_add(node_factory):
disconnects = ['-WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
if EXPERIMENTAL_DUAL_FUND:
disconnects = ['=WIRE_COMMITMENT_SIGNED'] + disconnects
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500, 7500))
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundchannel(l2, 10**6)
amt = 200000000
inv = l2.rpc.invoice(amt, 'testpayment2', 'desc')
rhash = inv['payment_hash']
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
l1.rpc.sendpay(route, rhash, payment_secret=inv['payment_secret'])
for i in range(len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid'
@pytest.mark.developer
def test_reconnect_receiver_fulfill(node_factory):
# Ordering matters: after +WIRE_UPDATE_FULFILL_HTLC, channeld
# will continue and try to send WIRE_COMMITMENT_SIGNED: if
# that's the next failure, it will do two in one run.
disconnects = ['+WIRE_UPDATE_FULFILL_HTLC',
'-WIRE_UPDATE_FULFILL_HTLC',
'-WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundchannel(l2, 10**6)
amt = 200000000
inv = l2.rpc.invoice(amt, 'testpayment2', 'desc')
rhash = inv['payment_hash']
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
l1.rpc.sendpay(route, rhash, payment_secret=inv['payment_secret'])
for i in range(len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid'
@flaky
@pytest.mark.developer
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_shutdown_reconnect(node_factory):
disconnects = ['-WIRE_SHUTDOWN',
'+WIRE_SHUTDOWN']
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
chan, _ = l1.fundchannel(l2, 10**6)
l1.pay(l2, 200000000)
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0
# This should wait until we're closed.
l1.rpc.close(chan)
l1.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
l2.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
l1.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
l2.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
# And should put closing into mempool (happens async, so
# CLOSINGD_COMPLETE may come first).
l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1
@flaky
@pytest.mark.developer
def test_reconnect_remote_sends_no_sigs(node_factory):
"""We re-announce, even when remote node doesn't send its announcement_signatures on reconnect.
"""
l1, l2 = node_factory.line_graph(2, wait_for_announce=True, opts={'may_reconnect': True})
# When l1 restarts (with rescan=1), make it think it hasn't
# reached announce_depth, so it wont re-send announcement_signatures
def no_blocks_above(req):
if req['params'][0] > 107:
return {"result": None,
"error": {"code": -8, "message": "Block height out of range"}, "id": req['id']}
else:
return {'result': l1.bitcoin.rpc.getblockhash(req['params'][0]),
"error": None, 'id': req['id']}
l1.daemon.rpcproxy.mock_rpc('getblockhash', no_blocks_above)
l1.restart()
# l2 will now uses (REMOTE's) announcement_signatures it has stored
wait_for(lambda: only_one(l2.rpc.listpeers()['peers'][0]['channels'])['status'] == [
'CHANNELD_NORMAL:Reconnected, and reestablished.',
'CHANNELD_NORMAL:Funding transaction locked. Channel announced.'])
# But l2 still sends its own sigs on reconnect
l2.daemon.wait_for_logs([r'peer_out WIRE_ANNOUNCEMENT_SIGNATURES',
r'peer_out WIRE_ANNOUNCEMENT_SIGNATURES'])
# l1 only did send them the first time
assert(''.join(l1.daemon.logs).count(r'peer_out WIRE_ANNOUNCEMENT_SIGNATURES') == 1)
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_shutdown_awaiting_lockin(node_factory, bitcoind):
l1 = node_factory.get_node()
l2 = node_factory.get_node(options={'funding-confirms': 3})
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundwallet(10**6 + 1000000)
chanid = l1.rpc.fundchannel(l2.info['id'], 10**6)['channel_id']
# Technically, this is async to fundchannel.
l1.daemon.wait_for_log('sendrawtx exit 0')
bitcoind.generate_block(1)
l1.rpc.close(chanid)
l1_state = 'DUALOPEND' if l1.config('experimental-dual-fund') else 'CHANNELD'
l2_state = 'DUALOPEND' if l1.config('experimental-dual-fund') else 'CHANNELD'
l1.daemon.wait_for_log('{}_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN'.format(l1_state))
l2.daemon.wait_for_log('{}_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN'.format(l2_state))
l1.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE')
l2.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE')
# And should put closing into mempool (happens async, so
# CLOSINGD_COMPLETE may come first).
l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
assert bitcoind.rpc.getmempoolinfo()['size'] == 1
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
l2.daemon.wait_for_log(' to ONCHAIN')
bitcoind.generate_block(100)
wait_for(lambda: l1.rpc.listpeers()['peers'] == [])
wait_for(lambda: l2.rpc.listpeers()['peers'] == [])
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_funding_change(node_factory, bitcoind):
"""Add some funds, fund a channel, and make sure we remember the change
"""
l1, l2 = node_factory.line_graph(2, fundchannel=False)
l1.fundwallet(10000000)
bitcoind.generate_block(1)
sync_blockheight(bitcoind, [l1])
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
assert only_one(outputs)['value'] == 10000000
l1.rpc.fundchannel(l2.info['id'], 1000000)
bitcoind.generate_block(1, wait_for_mempool=1)
sync_blockheight(bitcoind, [l1])
outputs = {r['status']: r['value'] for r in l1.db_query(
'SELECT status, SUM(value) AS value FROM outputs GROUP BY status;')}
# The 10m out is spent and we have a change output of 9m-fee
assert outputs[0] > 8990000
assert outputs[2] == 10000000
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_funding_all(node_factory, bitcoind):
"""Add some funds, fund a channel using all funds, make sure no funds remain
"""
l1, l2 = node_factory.line_graph(2, fundchannel=False)
l1.fundwallet(0.1 * 10**8)
bitcoind.generate_block(1)
sync_blockheight(bitcoind, [l1])
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
assert only_one(outputs)['value'] == 10000000
l1.rpc.fundchannel(l2.info['id'], "all")
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
assert len(outputs) == 0
@pytest.mark.openchannel('v1')
@pytest.mark.openchannel('v2')
def test_funding_all_too_much(node_factory):
"""Add more than max possible funds, fund a channel using all funds we can.
"""
l1, l2 = node_factory.line_graph(2, fundchannel=False)
addr, txid = l1.fundwallet(2**24 + 10000)
l1.rpc.fundchannel(l2.info['id'], "all")
# One reserved, confirmed output spent above, and one change.
outputs = l1.rpc.listfunds()['outputs']
spent = only_one([o for o in outputs if o['status'] == 'confirmed'])
assert spent['txid'] == txid