task_division_prb.cpp

# include <cstdlib>
# include <iostream>
# include <iomanip>
# include <ctime>
# include <cmath>

using namespace std;

# include "task_division.hpp"

int main ( int argc, char *argv[] );

//****************************************************************************80

int main ( int argc, char *argv[] )

//****************************************************************************80
//
//  Purpose:
//
//    MAIN is the main program for TASK_DIVISION_PRB.
//
//  Discussion:
//
//    TASK_DIVISION_PRB tests the TASK_DIVISION library.
//
//    This program simply demonstrates how one might automate the
//    assignment of T tasks to P processors, assuming that the assignment
//    is to be beforehand.
//
//    In that case, we just want to make sure that we assign each task
//    to a processor, that we assign about the same number of tasks
//    to each processor, and that we assign each processor a contiguous
//    range of tasks, say tasks I_LO to I_HI.
//
//    The routine that is called simulates this process.
//
//  Licensing:
//
//    This code is distributed under the GNU LGPL license. 
//
//  Modified:
//
//    23 October 2011
//
//  Author:
//
//    John Burkardt
//
{
  int proc_first;
  int proc_last;
  int task_number;

  timestamp ( );
  cout << "\n";
  cout << "TASK_DIVISION_PRB:\n";
  cout << "  C++ version\n";
  cout << "  Test the TASK_DIVISION library.\n";
  cout << "  Demonstrate how to automate the division of\n";
  cout << "  T tasks among a range of P processors\n";
  cout << "  indexed from PROC_FIRST to PROC_LAST.\n";

  task_number = 23;
  proc_first = 0;
  proc_last = 3;
  task_division ( task_number, proc_first, proc_last );

  task_number = 17;
  proc_first = 1;
  proc_last = 6;
  task_division ( task_number, proc_first, proc_last );

  task_number = 17;
  proc_first = 4;
  proc_last = 6;
  task_division ( task_number, proc_first, proc_last );

  task_number = 5;
  proc_first = -2;
  proc_last = 6;
  task_division ( task_number, proc_first, proc_last );

  task_number = 5;
  proc_first = 0;
  proc_last = 4;
  task_division ( task_number, proc_first, proc_last );

  task_number = 5;
  proc_first = 0;
  proc_last = 0;
  task_division ( task_number, proc_first, proc_last );

  task_number = 1000;
  proc_first = 1;
  proc_last = 17;
  task_division ( task_number, proc_first, proc_last );
//
//  Terminate.
//
  cout << "\n";
  cout << "TASK_DIVISION_PRB:\n";
  cout << "  Normal end of execution.\n";
  cout << "\n";
  timestamp ( );

  return 0;
}