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KthSmallestElementInABst.cpp
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KthSmallestElementInABst.cpp
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// Source : https://leetcode.com/problems/kth-smallest-element-in-a-bst/
// Author : Hao Chen
// Date : 2015-07-03
/**********************************************************************************
*
* Given a binary search tree, write a function kthSmallest to find the kth smallest element in it.
*
* Note:
* You may assume k is always valid, 1 ≤ k ≤ BST's total elements.
*
* Follow up:
* What if the BST is modified (insert/delete operations) often and you need to find the kth smallest frequently?
* How would you optimize the kthSmallest routine?
*
* Try to utilize the property of a BST.
* What if you could modify the BST node's structure?
* The optimal runtime complexity is O(height of BST).
*
* Credits:Special thanks to @ts for adding this problem and creating all test cases.
**********************************************************************************/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
// in-order travel - recursive way
int kthSmallestHelper_recursive(TreeNode* root, int& k) {
if (root==NULL) return 0; //this behavior is undefined!
//in-order travel
int result = kthSmallestHelper_recursive(root->left, k);
if (k==0) return result;
k--;
if (k==0) return root->val;
return kthSmallestHelper_recursive(root->right, k);
}
// in-order travel - non-recursive way
int kthSmallestHelper_nonRecursive(TreeNode* root, int k){
stack<TreeNode*> s;
while(!s.empty() || root){
while (root) {
s.push(root);
root = root->left;
}
k--;
root = s.top()->right;
if (k==0) return s.top()->val;
s.pop();
}
return -1;
}
int kthSmallest(TreeNode* root, int k) {
//return kthSmallestHelper_nonRecursive(root, k);
return kthSmallestHelper_recursive(root, k);
}
};