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s0011_container_with_most_water.rs
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/**
* [11] Container With Most Water
*
* Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
*
* Note: You may not slant the container and n is at least 2.
*
*
*
* <img alt="" src="https://s3-lc-upload.s3.amazonaws.com/uploads/2018/07/17/question_11.jpg" style="width: 600px; height: 287px;" />
*
* <small>The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49. </small>
*
*
*
* Example:
*
*
* Input: [1,8,6,2,5,4,8,3,7]
* Output: 49
*
*/
pub struct Solution {}
// problem: https://leetcode.com/problems/container-with-most-water/
// discuss: https://leetcode.com/problems/container-with-most-water/discuss/?currentPage=1&orderBy=most_votes&query=
// submission codes start here
// Brute force: O(N^2)
// Two Pointer: a[0] -> <- a[n-1]
impl Solution {
pub fn max_area(height: Vec<i32>) -> i32 {
let (mut start, mut end) = (0_usize, (height.len() - 1));
let mut max: i32 = (end - start) as i32 * Solution::min(height[start], height[end]);
let mut curr_area: i32 = 0;
while end - start > 1 {
// move the lower one
if height[start] < height[end] {
start += 1;
if height[start] < height[start - 1] {
continue;
}
} else {
end -= 1;
if height[end] < height[end + 1] {
continue;
}
}
curr_area = (end - start) as i32 * Solution::min(height[start], height[end]);
if curr_area > max {
max = curr_area
}
}
max
}
#[inline(always)]
fn min(i: i32, j: i32) -> i32 {
if i > j {
j
} else {
i
}
}
}
// submission codes end
#[cfg(test)]
mod tests {
use super::*;
#[test]
fn test_11() {
assert_eq!(Solution::max_area(vec![1, 8, 6, 2, 5, 4, 8, 3, 7]), 49);
assert_eq!(Solution::max_area(vec![6, 9]), 6);
assert_eq!(Solution::max_area(vec![1, 1, 2, 1, 1, 1]), 5);
}
}