forked from sachuverma/DataStructures-Algorithms
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathEvaluate Reverse Polish Notation.cpp
80 lines (74 loc) · 1.67 KB
/
Evaluate Reverse Polish Notation.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
/*
Evaluate Reverse Polish Notation
================================
Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +, -, *, /. Each operand may be an integer or another expression.
Note:
Division between two integers should truncate toward zero.
The given RPN expression is always valid. That means the expression would always evaluate to a result and there won't be any divide by zero operation.
Example 1:
Input: ["2", "1", "+", "3", "*"]
Output: 9
Explanation: ((2 + 1) * 3) = 9
Example 2:
Input: ["4", "13", "5", "/", "+"]
Output: 6
Explanation: (4 + (13 / 5)) = 6
Example 3:
Input: ["10", "6", "9", "3", "+", "-11", "*", "/", "*", "17", "+", "5", "+"]
Output: 22
Explanation:
((10 * (6 / ((9 + 3) * -11))) + 17) + 5
= ((10 * (6 / (12 * -11))) + 17) + 5
= ((10 * (6 / -132)) + 17) + 5
= ((10 * 0) + 17) + 5
= (0 + 17) + 5
= 17 + 5
= 22
*/
class Solution
{
public:
int evalRPN(vector<string> &tokens)
{
stack<int> s;
for (auto &token : tokens)
{
if (token == "+")
{
int n1 = s.top();
s.pop();
int n2 = s.top();
s.pop();
s.push(n1 + n2);
}
else if (token == "-")
{
int n1 = s.top();
s.pop();
int n2 = s.top();
s.pop();
s.push(n2 - n1);
}
else if (token == "*")
{
int n1 = s.top();
s.pop();
int n2 = s.top();
s.pop();
s.push(n1 * n2);
}
else if (token == "/")
{
int n1 = s.top();
s.pop();
int n2 = s.top();
s.pop();
s.push(n2 / n1);
}
else
s.push(stoi(token));
}
return s.top();
}
};