search-insert-position.py

# Time:  O(logn)
# Space: O(1)
#
# Given a sorted array and a target value, return the index if the target is found.
# 
# If not, return the index where it would be if it were inserted in order.
# 
# You may assume no duplicates in the array.
# 
# Here are few examples.
# [1,3,5,6], 5 -> 2
# [1,3,5,6], 2 -> 1
# [1,3,5,6], 7 -> 4
# [1,3,5,6], 0 -> 0
#

class Solution(object):
    def searchInsert(self, nums, target):
        """
        :type nums: List[int]
        :type target: int
        :rtype: int
        """
        left, right = 0, len(nums) - 1
        while left <= right:
            mid = left + (right - left) / 2
            if nums[mid] >= target:
                right = mid - 1
            else:
                left = mid + 1

        return left


if __name__ == "__main__":
    print Solution().searchInsert([1, 3, 5, 6], 5)
    print Solution().searchInsert([1, 3, 5, 6], 2)
    print Solution().searchInsert([1, 3, 5, 6], 7)
    print Solution().searchInsert([1, 3, 5, 6], 0)