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s0098_validate_binary_search_tree.rs
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/**
* [98] Validate Binary Search Tree
*
* Given a binary tree, determine if it is a valid binary search tree (BST).
*
* Assume a BST is defined as follows:
*
*
* The left subtree of a node contains only nodes with keys less than the node's key.
* The right subtree of a node contains only nodes with keys greater than the node's key.
* Both the left and right subtrees must also be binary search trees.
*
*
* Example 1:
*
*
* Input:
* 2
* / \
* 1 3
* Output: true
*
*
* Example 2:
*
*
* 5
* / \
* 1 4
* / \
* 3 6
* Output: false
* Explanation: The input is: [5,1,4,null,null,3,6]. The root node's value
* is 5 but its right child's value is 4.
*
*
*/
pub struct Solution {}
// problem: https://leetcode.com/problems/validate-binary-search-tree/
// discuss: https://leetcode.com/problems/validate-binary-search-tree/discuss/?currentPage=1&orderBy=most_votes&query=
// submission codes start here
// Definition for a binary tree node.
use crate::util::tree::{to_tree, TreeNode};
use std::cell::RefCell;
use std::rc::Rc;
impl Solution {
pub fn is_valid_bst(root: Option<Rc<RefCell<TreeNode>>>) -> bool {
let mut vec = vec![];
Solution::preorder_traverse(root.as_ref(), &mut vec)
}
fn preorder_traverse(
root: Option<&Rc<RefCell<TreeNode>>>,
formers: &mut Vec<(i32, i32)>,
) -> bool {
if let Some(node) = root {
let root_val = root.as_ref().unwrap().borrow().val;
for former in formers.iter() {
if (former.0 < 0 && root_val >= former.1) || (former.0 > 0 && root_val <= former.1)
{
return false;
}
}
let mut to_right = formers.clone();
formers.push((-1, root_val));
to_right.push((1, root_val));
Solution::preorder_traverse(node.borrow().left.as_ref(), formers)
&& Solution::preorder_traverse(node.borrow().right.as_ref(), &mut to_right)
} else {
true
}
}
}
// submission codes end
#[cfg(test)]
mod tests {
use super::*;
#[test]
fn test_98() {
assert_eq!(
Solution::is_valid_bst(tree![5, 1, 4, null, null, 3, 6]),
false
);
assert_eq!(Solution::is_valid_bst(tree![2, 1, 3]), true);
assert_eq!(
Solution::is_valid_bst(tree![10, 5, 15, null, null, 6, 20]),
false
);
}
}