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n0040_combination_sum_ii.rs
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/**
* [40] Combination Sum II
*
* Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target.
*
* Each number in candidates may only be used once in the combination.
*
* Note:
*
*
* All numbers (including target) will be positive integers.
* The solution set must not contain duplicate combinations.
*
*
* Example 1:
*
*
* Input: candidates = [10,1,2,7,6,1,5], target = 8,
* A solution set is:
* [
* [1, 7],
* [1, 2, 5],
* [2, 6],
* [1, 1, 6]
* ]
*
*
* Example 2:
*
*
* Input: candidates = [2,5,2,1,2], target = 5,
* A solution set is:
* [
* [1,2,2],
* [5]
* ]
*
*
*/
pub struct Solution {}
// submission codes start here
impl Solution {
pub fn combination_sum2(candidates: Vec<i32>, target: i32) -> Vec<Vec<i32>> {
let mut seq = candidates;
let mut res = Vec::new();
seq.sort_unstable_by(|a, b| b.cmp(a));
let mut vec = Vec::new();
Solution::backtrack(&seq, target, vec, &mut res, 0);
res
}
fn backtrack(
seq: &Vec<i32>,
target: i32,
mut curr: Vec<i32>,
result: &mut Vec<Vec<i32>>,
start_idx: usize,
) {
let mut i = start_idx;
while i < seq.len() {
let item = seq[i];
if target - item < 0 {
i += 1;
continue;
}
let mut new_vec = curr.clone();
new_vec.push(item);
if target == item {
result.push(new_vec);
} else {
Solution::backtrack(seq, target - item, new_vec, result, i + 1);
}
// skip duplicate result
while i < seq.len() && seq[i] == item {
i += 1;
}
}
}
}
// submission codes end
#[cfg(test)]
mod tests {
use super::*;
#[test]
fn test_40() {
assert_eq!(
Solution::combination_sum2(vec![1, 1, 1, 1, 1, 1, 1], 7),
vec![vec![1, 1, 1, 1, 1, 1, 1]]
);
assert_eq!(
Solution::combination_sum2(vec![10, 1, 2, 7, 6, 1, 5], 8),
vec![vec![7, 1], vec![6, 2], vec![6, 1, 1], vec![5, 2, 1],]
);
assert_eq!(
Solution::combination_sum2(vec![2, 5, 2, 1, 2], 5),
vec![vec![5], vec![2, 2, 1],]
);
}
}