Given two strings s
and t
, return true
if s
is a subsequence of t
, or false
otherwise.
A subsequence of a string is a new string that is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (i.e., "ace"
is a subsequence of "abcde"
while "aec"
is not).
Input: s = "abc", t = "ahbgdc"
Output: true
Input: s = "axc", t = "ahbgdc"
Output: false
0 <= s.length <= 100
0 <= t.length <= 10^4
s
andt
consist only of lowercase English letters.
-
Time complexity:
O(n)
-
Space complexity:
O(1)
class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
n, m = len(s), len(t)
if n > m:
return False
if n == 0:
return True
j = 0
for i in range(m):
if j < n and s[j] == t[i]:
j += 1
return j == n
class Solution {
public boolean isSubsequence(String s, String t) {
int n = s.length();
int m = t.length();
if (n > m) {
return false;
}
if (n == 0) {
return true;
}
int j = 0;
for (int i = 0; i < m && j < n; i++) {
if (s.charAt(j) == t.charAt(i)) {
j++;
}
}
return j == n;
}
}
class Solution {
public:
bool isSubsequence(string s, string t) {
int n = s.length();
int m = t.length();
int j = 0;
for (int i = 0; i < m && j < n; i++) {
if (s[j] == t[i]) {
j++;
}
}
return j == n;
}
};