https://leetcode.com/problems/evaluate-reverse-polish-notation/description/
Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +, -, *, /. Each operand may be an integer or another expression.
Note:
Division between two integers should truncate toward zero.
The given RPN expression is always valid. That means the expression would always evaluate to a result and there won't be any divide by zero operation.
逆波兰表达式又叫做后缀表达式。在通常的表达式中,二元运算符总是置于与之相关的两个运算对象之间,这种表示法也称为中缀表示
。
波兰逻辑学家J.Lukasiewicz于1929年提出了另一种表示表达式的方法,按此方法,每一运算符都置于其运算对象之后,故称为后缀表示
。
逆波兰表达式是一种十分有用的表达式,它将复杂表达式转换为可以依靠简单的操作得到计算结果的表达式。例如(a+b)(c+d)转换为ab+cd+
-
栈的基本用法
-
如果你用的是JS的话,需要注意/ 和 其他很多语言是不一样的
-
如果你用的是JS的话,需要先将字符串转化为数字。否则有很多意想不到的结果
-
操作符的顺序应该是 先出栈的是第二位,后出栈的是第一位。 这在不符合交换律的操作中很重要, 比如减法和除法。
/*
* @lc app=leetcode id=150 lang=javascript
*
* [150] Evaluate Reverse Polish Notation
*
* https://leetcode.com/problems/evaluate-reverse-polish-notation/description/
*
* algorithms
* Medium (31.43%)
* Total Accepted: 153.3K
* Total Submissions: 485.8K
* Testcase Example: '["2","1","+","3","*"]'
*
* Evaluate the value of an arithmetic expression in Reverse Polish Notation.
*
* Valid operators are +, -, *, /. Each operand may be an integer or another
* expression.
*
* Note:
*
*
* Division between two integers should truncate toward zero.
* The given RPN expression is always valid. That means the expression would
* always evaluate to a result and there won't be any divide by zero
* operation.
*
*
* Example 1:
*
*
* Input: ["2", "1", "+", "3", "*"]
* Output: 9
* Explanation: ((2 + 1) * 3) = 9
*
*
* Example 2:
*
*
* Input: ["4", "13", "5", "/", "+"]
* Output: 6
* Explanation: (4 + (13 / 5)) = 6
*
*
* Example 3:
*
*
* Input: ["10", "6", "9", "3", "+", "-11", "*", "/", "*", "17", "+", "5", "+"]
* Output: 22
* Explanation:
* ((10 * (6 / ((9 + 3) * -11))) + 17) + 5
* = ((10 * (6 / (12 * -11))) + 17) + 5
* = ((10 * (6 / -132)) + 17) + 5
* = ((10 * 0) + 17) + 5
* = (0 + 17) + 5
* = 17 + 5
* = 22
*
*
*/
/**
* @param {string[]} tokens
* @return {number}
*/
var evalRPN = function(tokens) {
const stack = [];
for (let index = 0; index < tokens.length; index++) {
const token = tokens[index];
if (!Number.isNaN(Number(token))) {
stack.push(token);
} else {
const a = Number(stack.pop());
const b = Number(stack.pop());
if (token === "*") {
stack.push(a * b);
} else if (token === "/") {
stack.push(b / a > 0 ? Math.floor(b / a) : Math.ceil(b / a));
} else if (token === "+") {
stack.push(a + b);
} else if (token === "-") {
stack.push(b - a);
}
}
}
return stack.pop();
};