README_EN.md

1281. Subtract the Product and Sum of Digits of an Integer

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Description

Given an integer number n, return the difference between the product of its digits and the sum of its digits.

 

Example 1:

Input: n = 234
Output: 15 
Explanation: 
Product of digits = 2 * 3 * 4 = 24 
Sum of digits = 2 + 3 + 4 = 9 
Result = 24 - 9 = 15

Example 2:

Input: n = 4421
Output: 21
Explanation: 
Product of digits = 4 * 4 * 2 * 1 = 32 
Sum of digits = 4 + 4 + 2 + 1 = 11 
Result = 32 - 11 = 21

 

Constraints:

• 1 <= n <= 10^5

Solutions

Python3

class Solution:
    def subtractProductAndSum(self, n: int) -> int:
        s, p = 0, 1
        while n:
            t = n % 10
            n //= 10
            s += t
            p *= t
        return p - s

Java

class Solution {
    public int subtractProductAndSum(int n) {
        int s = 0, p = 1;
        while (n != 0) {
            int t = n % 10;
            n /= 10;
            s += t;
            p *= t;
        }
        return p - s;
    }
}

C++

class Solution {
public:
    int subtractProductAndSum(int n) {
        int s = 0, p = 1;
        while (n) {
            int t = n % 10;
            n /= 10;
            s += t;
            p *= t;
        }
        return p - s;
    }
};

Go

func subtractProductAndSum(n int) int {
	s, p := 0, 1
	for n != 0 {
		t := n % 10
		n /= 10
		s += t
		p *= t
	}
	return p - s
}

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