README_EN.md

1920. Build Array from Permutation

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Description

Given a zero-based permutation nums (0-indexed), build an array ans of the same length where ans[i] = nums[nums[i]] for each 0 <= i < nums.length and return it.

A zero-based permutation nums is an array of distinct integers from 0 to nums.length - 1 (inclusive).

 

Example 1:

Input: nums = [0,2,1,5,3,4]
Output: [0,1,2,4,5,3]
Explanation: The array ans is built as follows: 
ans = [nums[nums[0]], nums[nums[1]], nums[nums[2]], nums[nums[3]], nums[nums[4]], nums[nums[5]]]
    = [nums[0], nums[2], nums[1], nums[5], nums[3], nums[4]]
    = [0,1,2,4,5,3]

Example 2:

Input: nums = [5,0,1,2,3,4]
Output: [4,5,0,1,2,3]
Explanation: The array ans is built as follows:
ans = [nums[nums[0]], nums[nums[1]], nums[nums[2]], nums[nums[3]], nums[nums[4]], nums[nums[5]]]
    = [nums[5], nums[0], nums[1], nums[2], nums[3], nums[4]]
    = [4,5,0,1,2,3]

 

Constraints:

• 1 <= nums.length <= 1000
• 0 <= nums[i] < nums.length
• The elements in nums are distinct.

Solutions

Python3

class Solution:
    def buildArray(self, nums: List[int]) -> List[int]:
        return [nums[num] for num in nums]

Java

class Solution {
    public int[] buildArray(int[] nums) {
        int[] ans = new int[nums.length];
        for (int i = 0; i < nums.length; ++i) {
            ans[i] = nums[nums[i]];
        }
        return ans;
    }
}

JavaScript

/**
 * @param {number[]} nums
 * @return {number[]}
 */
var buildArray = function(nums) {
    let ans = [];
    for (let i = 0; i < nums.length; ++i) {
        ans[i] = nums[nums[i]];
    }
    return ans;
};

C++

class Solution {
public:
    vector<int> buildArray(vector<int>& nums) {
        vector<int> ans;
        for (int& num : nums) {
            ans.push_back(nums[num]);
        }
        return ans;
    }
};

Go

func buildArray(nums []int) []int {
	ans := make([]int, len(nums))
	for i, num := range nums {
		ans[i] = nums[num]
	}
	return ans
}

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