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szcf-weiya committed Nov 3, 2019
1 parent 8612f8b commit bc87393
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Expand Up @@ -126,7 +126,7 @@ $$
> $$
> 式中
> $$
> S=U^TV
> S=U^TAV
> $$
> 若选择$U$和$V$为正交矩阵,则他们的选择各存在$n^2-n$个自由度.他提出利用这些自由度使矩阵$S$的非对角元为0,即矩阵$S=\Sigma=diag(\sigma_1,\sigma_2,\ldots,\sigma_n)$为对角矩阵.则
> $$
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