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""" | ||
Author : Turfa Auliarachman | ||
Date : October 12, 2016 | ||
This is a pure Python implementation of Dynamic Programming solution to the edit distance problem. | ||
The problem is : | ||
Given two strings A and B. Find the minimum number of operations to string B such that A = B. The permitted operations are removal, insertion, and substitution. | ||
""" | ||
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class EditDistance: | ||
""" | ||
Use : | ||
solver = EditDistance() | ||
editDistanceResult = solver.solve(firstString, secondString) | ||
""" | ||
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def __init__(self): | ||
self.__prepare__() | ||
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def __prepare__(self, N = 0, M = 0): | ||
self.dp = [[-1 for y in range(0,M)] for x in range(0,N)] | ||
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def __solveDP(self, x, y): | ||
if (x==-1): | ||
return y+1 | ||
elif (y==-1): | ||
return x+1 | ||
elif (self.dp[x][y]>-1): | ||
return self.dp[x][y] | ||
else: | ||
if (self.A[x]==self.B[y]): | ||
self.dp[x][y] = self.__solveDP(x-1,y-1) | ||
else: | ||
self.dp[x][y] = 1+min(self.__solveDP(x,y-1), self.__solveDP(x-1,y), self.__solveDP(x-1,y-1)) | ||
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return self.dp[x][y] | ||
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def solve(self, A, B): | ||
if isinstance(A,bytes): | ||
A = A.decode('ascii') | ||
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if isinstance(B,bytes): | ||
B = B.decode('ascii') | ||
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self.A = str(A) | ||
self.B = str(B) | ||
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self.__prepare__(len(A), len(B)) | ||
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return self.__solveDP(len(A)-1, len(B)-1) | ||
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if __name__ == '__main__': | ||
import sys | ||
if sys.version_info.major < 3: | ||
input_function = raw_input | ||
else: | ||
input_function = input | ||
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solver = EditDistance() | ||
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print("****************** Testing Edit Distance DP Algorithm ******************") | ||
print() | ||
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print("Enter the first string: ", end="") | ||
S1 = input_function() | ||
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print("Enter the second string: ", end="") | ||
S2 = input_function() | ||
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print() | ||
print("The minimum Edit Distance is: %d" % (solver.solve(S1, S2))) | ||
print() | ||
print("*************** End of Testing Edit Distance DP Algorithm ***************") |