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padata_stop() has two callers and is unnecessary in both cases. When pcrypt calls it before padata_free(), it's being unloaded so there are no outstanding padata jobs[0]. When __padata_free() calls it, it's either along the same path or else pcrypt initialization failed, which of course means there are also no outstanding jobs. Removing it simplifies padata and saves text. [0] https://lore.kernel.org/linux-crypto/[email protected]/ Signed-off-by: Daniel Jordan <[email protected]> Cc: Herbert Xu <[email protected]> Cc: Steffen Klassert <[email protected]> Cc: [email protected] Cc: [email protected] Signed-off-by: Herbert Xu <[email protected]>
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