Update 88.merge-sorted-array.md

problems/88.merge-sorted-array.md

@@ -1,23 +1,23 @@
 ## 题目地址
 
-https://leetcode.com/problems/merge-sorted-array/description/
+https://leetcode-cn.com/problems/merge-sorted-array/
 
 ## 题目描述
 
 ```
-Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
+给定两个有序整数数组 nums1 和 nums2，将 nums2 合并到 nums1 中，使得 num1 成为一个有序数组。
 
-Note:
+说明:
 
-The number of elements initialized in nums1 and nums2 are m and n respectively.
-You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
-Example:
+初始化 nums1 和 nums2 的元素数量分别为 m 和 n。
+你可以假设 nums1 有足够的空间（空间大小大于或等于 m + n）来保存 nums2 中的元素。
+示例:
 
-Input:
+输入:
 nums1 = [1,2,3,0,0,0], m = 3
 nums2 = [2,5,6],       n = 3
 
-Output: [1,2,2,3,5,6]
+输出: [1,2,2,3,5,6]
 ```
 
 ## 思路
@@ -102,50 +102,12 @@ function merge(nums1, nums2) {
 
 ## 代码
 
+代码支持：Python3， C++， JavaScript
+
+
+JavaSCript Code:
+
 ```js
-/*
- * @lc app=leetcode id=88 lang=javascript
- *
- * [88] Merge Sorted Array
- *
- * https://leetcode.com/problems/merge-sorted-array/description/
- *
- * algorithms
- * Easy (34.95%)
- * Total Accepted:    347.5K
- * Total Submissions: 984.7K
- * Testcase Example:  '[1,2,3,0,0,0]\n3\n[2,5,6]\n3'
- *
- * Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as
- * one sorted array.
- *
- * Note:
- *
- *
- * The number of elements initialized in nums1 and nums2 are m and n
- * respectively.
- * You may assume that nums1 has enough space (size that is greater or equal to
- * m + n) to hold additional elements from nums2.
- *
- *
- * Example:
- *
- *
- * Input:
- * nums1 = [1,2,3,0,0,0], m = 3
- * nums2 = [2,5,6],       n = 3
- *
- * Output: [1,2,2,3,5,6]
- *
- *
- */
-/**
- * @param {number[]} nums1
- * @param {number} m
- * @param {number[]} nums2
- * @param {number} n
- * @return {void} Do not return anything, modify nums1 in-place instead.
- */
 var merge = function(nums1, m, nums2, n) {
   // 设置一个指针，指针初始化指向nums1的末尾（根据#62，应该是index为 m+n-1 的位置，因为nums1的长度有可能更长）
   // 然后不断左移指针更新元素
@@ -175,7 +137,7 @@ var merge = function(nums1, m, nums2, n) {
   }
 };
 ```
-模仿上述代码，思路相同
+
 C++ code:
 ```
 class Solution {
@@ -199,7 +161,7 @@ public:
 };
 ```
 
-Python 代码
+Python Code
 ```python
 class Solution:
     def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None:
@@ -222,3 +184,12 @@ class Solution:
         if n > 0:
             nums1[:n] = nums2[:n]
 ```
+
+
+**复杂度分析**
+- 时间复杂度：$O(M + N)$
+- 空间复杂度：$O(1)$
+
+欢迎关注我的公众号《脑洞前端》获取更多更新鲜的LeetCode题解
+
+![](https://pic.leetcode-cn.com/89ef69abbf02a2957838499a96ce3fbb26830aae52e3ab90392e328c2670cddc-file_1581478989502)