Create 690.EmployeeImportance.py

Easy/690.EmployeeImportance.py

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+'''
+    You are given a data structure of employee information, 
+    which includes the employee's unique id, their importance 
+    value and their direct subordinates' id.
+
+    For example, employee 1 is the leader of employee 2, and 
+    employee 2 is the leader of employee 3. They have 
+    importance value 15, 10 and 5, respectively. Then 
+    employee 1 has a data structure like [1, 15, [2]], and 
+    employee 2 has [2, 10, [3]], and employee 3 has [3, 5, []]. 
+    Note that although employee 3 is also a subordinate of 
+    employee 1, the relationship is not direct.
+
+    Now given the employee information of a company, and an 
+    employee id, you need to return the total importance 
+    value of this employee and all their subordinates.
+
+    Example:
+    Input: [[1, 5, [2, 3]], [2, 3, []], [3, 3, []]], 1
+    Output: 11
+    Explanation: Employee 1 has importance value 5, and he 
+                 has two direct subordinates: employee 2 
+                 and employee 3. They both have importance 
+                 value 3. So the total importance value of 
+                 employee 1 is 5 + 3 + 3 = 11.
+
+    Note:
+        1. One employee has at most one direct leader and 
+           may have several subordinates.
+        2. The maximum number of employees won't exceed 2000.
+'''
+#Difficulty: Easy
+#108 / 108 test cases passed.
+#Runtime: 152 ms
+#Memory Usage: 15.4 MB
+
+#Runtime: 152 ms, faster than 87.55% of Python3 online submissions for Employee Importance.
+#Memory Usage: 15.4 MB, less than 81.67% of Python3 online submissions for Employee Importance.
+
+"""
+# Definition for Employee.
+class Employee:
+    def __init__(self, id: int, importance: int, subordinates: List[int]):
+        self.id = id
+        self.importance = importance
+        self.subordinates = subordinates
+"""
+
+class Solution:
+
+    def getImportance(self, employees: List['Employee'], id: int) -> int:
+
+        db = {}
+        queue = [id]
+        importance = 0
+
+        '''
+        Creating Database of employees.
+        '''
+        for employee in employees:
+            db[employee.id] = employee
+
+        """
+        Gathering value of current employee and all 
+        their subordinates.
+        """
+        while queue:
+            id = queue.pop(0)
+            queue.extend(db[id].subordinates)
+            importance += db[id].importance
+
+        return importance