compat_do_execve should unshare_files

2.6.26's commit fd8328b
"sanitize handling of shared descriptor tables in failing execve()"
moved the unshare_files() from flush_old_exec() and several binfmts
to the head of do_execve(); but forgot to make the same change to
compat_do_execve(), leaving a CLONE_FILES files_struct shared across
exec from a 32-bit process on a 64-bit kernel.

It's arguable whether the files_struct really ought to be unshared
across exec; but 2.6.1 made that so to stop the loading binary's fd
leaking into other threads, and a 32-bit process on a 64-bit kernel
ought to behave in the same way as 32 on 32 and 64 on 64.

Signed-off-by: Hugh Dickins <[email protected]>
Cc: [email protected]
Signed-off-by: Linus Torvalds <[email protected]>

fs/compat.c

@@ -1420,12 +1420,17 @@ int compat_do_execve(char * filename,
 {
 	struct linux_binprm *bprm;
 	struct file *file;
+	struct files_struct *displaced;
 	int retval;
 
+	retval = unshare_files(&displaced);
+	if (retval)
+		goto out_ret;
+
 	retval = -ENOMEM;
 	bprm = kzalloc(sizeof(*bprm), GFP_KERNEL);
 	if (!bprm)
-		goto out_ret;
+		goto out_files;
 
 	retval = mutex_lock_interruptible(&current->cred_exec_mutex);
 	if (retval < 0)
@@ -1487,6 +1492,8 @@ int compat_do_execve(char * filename,
 	mutex_unlock(&current->cred_exec_mutex);
 	acct_update_integrals(current);
 	free_bprm(bprm);
+	if (displaced)
+		put_files_struct(displaced);
 	return retval;
 
 out:
@@ -1506,6 +1513,9 @@ int compat_do_execve(char * filename,
 out_free:
 	free_bprm(bprm);
 
+out_files:
+	if (displaced)
+		reset_files_struct(displaced);
 out_ret:
 	return retval;
 }