ethoc: align received packet to make IP header at word boundary

The packet buffer is allocated at 4 bytes boundary, but the IP header length and version bits is located at byte 14. These bit fields access as 32 bits word and caused exception on processors that do not support unaligned access. The patch adds 2 bytes offset to make the bit fields word aligned. Signed-off-by: Thomas Chou <[email protected]> Signed-off-by: David S. Miller <[email protected]>
ambv · Oct 7, 2009 · 050f91d · 050f91d
1 parent 3ee19a8
commit 050f91d
Showing 1 changed file with 4 additions and 0 deletions.
diff --git a/drivers/net/ethoc.c b/drivers/net/ethoc.c
@@ -399,6 +399,10 @@ static int ethoc_rx(struct net_device *dev, int limit)
 		if (ethoc_update_rx_stats(priv, &bd) == 0) {
 			int size = bd.stat >> 16;
 			struct sk_buff *skb = netdev_alloc_skb(dev, size);
+
+			size -= 4; /* strip the CRC */
+			skb_reserve(skb, 2); /* align TCP/IP header */
+
 			if (likely(skb)) {
 				void *src = phys_to_virt(bd.addr);
 				memcpy_fromio(skb_put(skb, size), src, size);