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Adding sum of subsets (TheAlgorithms#929)
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def isSumSubset(arr, arrLen, requiredSum): | ||
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# a subset value says 1 if that subset sum can be formed else 0 | ||
#initially no subsets can be formed hence False/0 | ||
subset = ([[False for i in range(requiredSum + 1)] for i in range(arrLen + 1)]) | ||
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#for each arr value, a sum of zero(0) can be formed by not taking any element hence True/1 | ||
for i in range(arrLen + 1): | ||
subset[i][0] = True | ||
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#sum is not zero and set is empty then false | ||
for i in range(1, requiredSum + 1): | ||
subset[0][i] = False | ||
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for i in range(1, arrLen + 1): | ||
for j in range(1, requiredSum + 1): | ||
if arr[i-1]>j: | ||
subset[i][j] = subset[i-1][j] | ||
if arr[i-1]<=j: | ||
subset[i][j] = (subset[i-1][j] or subset[i-1][j-arr[i-1]]) | ||
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#uncomment to print the subset | ||
# for i in range(arrLen+1): | ||
# print(subset[i]) | ||
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return subset[arrLen][requiredSum] | ||
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arr = [2, 4, 6, 8] | ||
requiredSum = 5 | ||
arrLen = len(arr) | ||
if isSumSubset(arr, arrLen, requiredSum): | ||
print("Found a subset with required sum") | ||
else: | ||
print("No subset with required sum") |