Changed way to get current year so value is an integer (as required b…

…y the class). PHP's date function is intended for formatting and returns a string type as such. Signed-off-by: Sacha Telgenhof <[email protected]>
crossan007 · Feb 24, 2018 · bc23f0c · bc23f0c
1 parent 82ce112
commit bc23f0c
Showing 1 changed file with 2 additions and 2 deletions.
diff --git a/src/Yasumi/Yasumi.php b/src/Yasumi/Yasumi.php
@@ -89,7 +89,7 @@ public static function nextWorkingDay(
 
         while ($workingDays > 0) {
             $date = $date->add(new \DateInterval('P1D'));
-            if (! $provider || $provider->getYear() != $date->format('Y')) {
+            if (! $provider || $provider->getYear() !== \getdate()['year']) {
                 $provider = self::create($class, $date->format('Y'));
             }
             if ($provider->isWorkingDay($date)) {
@@ -285,7 +285,7 @@ public static function prevWorkingDay(
 
         while ($workingDays > 0) {
             $date = $date->sub(new \DateInterval('P1D'));
-            if (! $provider || $provider->getYear() != $date->format('Y')) {
+            if (! $provider || $provider->getYear() !== \getdate()['year']) {
                 $provider = self::create($class, $date->format('Y'));
             }
             if ($provider->isWorkingDay($date)) {