Merge ElementsProject#272: Fix confidential test to not assume fee ou…

…tput will be last of 3

3059856 Fix confidential test to not assume fee output will be last of 3 (Gregory Sanders)

qa/rpc-tests/confidential_transactions.py

@@ -167,14 +167,13 @@ def run_test(self):
         self.nodes[0].generate(101)
         self.sync_all()
 
-        txout0 = self.nodes[0].gettxout(txid, 0)
-        txout1 = self.nodes[0].gettxout(txid, 1)
-
-        if "asset" in txout0:
-            assert_equal(txout0["asset"], decodedtx["vout"][0]["asset"])
-        elif "asset" in txout1:
-            assert_equal(txout1["asset"], decodedtx["vout"][1]["asset"])
-        else:
+        unblindfound = False
+        for i in range(len(decodedtx["vout"])):
+            txout = self.nodes[0].gettxout(txid, i)
+            if txout is not None and "asset" in txout:
+                unblindfound = True
+
+        if unblindfound == False:
             raise Exception("No unconfidential output detected when one should exist")
 
         node0 -= value4