lib/ofpbuf: make ofpbuf_use() static

There is no external users for ofpbuf_use() directly. Signed-off-by: Andy Zhou <[email protected]> Acked-by: Ben Pfaff <[email protected]>
dhanunjaya · Sep 1, 2015 · 662eba3 · 662eba3
1 parent 2db0218
commit 662eba3
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Showing 2 changed files with 1 addition and 2 deletions.
diff --git a/lib/ofpbuf.c b/lib/ofpbuf.c
@@ -47,7 +47,7 @@ ofpbuf_use__(struct ofpbuf *b, void *base, size_t allocated, size_t size,
  * memory starting at 'base'.  'base' should be the first byte of a region
  * obtained from malloc().  It will be freed (with free()) if 'b' is resized or
  * freed. */
-void
+static void
 ofpbuf_use(struct ofpbuf *b, void *base, size_t allocated)
 {
     ofpbuf_use__(b, base, allocated, 0, OFPBUF_MALLOC);

diff --git a/lib/ofpbuf.h b/lib/ofpbuf.h
@@ -83,7 +83,6 @@ struct ofpbuf {
         .source = OFPBUF_STUB,                  \
     }
 
-void ofpbuf_use(struct ofpbuf *, void *, size_t);
 void ofpbuf_use_ds(struct ofpbuf *, const struct ds *);
 void ofpbuf_use_stack(struct ofpbuf *, void *, size_t);
 void ofpbuf_use_stub(struct ofpbuf *, void *, size_t);