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bfs and dfs of graphs in python
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jerryderry committed Dec 2, 2018
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88 changes: 88 additions & 0 deletions python/31_bfs_dfs/bfs_dfs.py
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"""
Breadth-first search and depth-first search.
Author: Wenru Dong
"""

from typing import List, Optional, Generator, IO
from collections import deque

class Graph:
"""Undirected graph."""
def __init__(self, num_vertices: int):
self._num_vertices = num_vertices
self._adjacency = [[] for _ in range(num_vertices)]

def add_edge(self, s: int, t: int) -> None:
self._adjacency[s].append(t)
self._adjacency[t].append(s)

def _generate_path(self, s: int, t: int, prev: List[Optional[int]]) -> Generator[str, None, None]:
if prev[t] or s != t:
yield from self._generate_path(s, prev[t], prev)
yield str(t)

def bfs(self, s: int, t: int) -> IO[str]:
"""Print out the path from Vertex s to Vertex t
using bfs.
"""
if s == t: return

visited = [False] * self._num_vertices
visited[s] = True
q = deque()
q.append(s)
prev = [None] * self._num_vertices

while q:
v = q.popleft()
for neighbour in self._adjacency[v]:
if not visited[neighbour]:
prev[neighbour] = v
if neighbour == t:
print("->".join(self._generate_path(s, t, prev)))
return
visited[neighbour] = True
q.append(neighbour)

def dfs(self, s: int, t: int) -> IO[str]:
"""Print out a path from Vertex s to Vertex t
using dfs.
"""
found = False
visited = [False] * self._num_vertices
prev = [None] * self._num_vertices

def _dfs(from_vertex: int) -> None:
nonlocal found
if found: return
visited[from_vertex] = True
if from_vertex == t:
found = True
return
for neighbour in self._adjacency[from_vertex]:
if not visited[neighbour]:
prev[neighbour] = from_vertex
_dfs(neighbour)

_dfs(s)
print("->".join(self._generate_path(s, t, prev)))


if __name__ == "__main__":

graph = Graph(8)

graph.add_edge(0, 1)
graph.add_edge(0, 3)
graph.add_edge(1, 2)
graph.add_edge(1, 4)
graph.add_edge(2, 5)
graph.add_edge(3, 4)
graph.add_edge(4, 5)
graph.add_edge(4, 6)
graph.add_edge(5, 7)
graph.add_edge(6, 7)

graph.bfs(0, 7)
graph.dfs(0, 7)

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