更新：量子力学、汇编程序设计基础 (QSCTech#61)

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汇编语言程序设计基础/Homework/HW01/HW1_3160______.asm

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+ASSUME CS:CODE, DS:DATA
+;define the data segment
+DATA SEGMENT
+	GREEN_HIGH   	DB  0
+    GREEN_LOW   	DB  0
+    BLUE_H   		DB  0
+    BLUE_M   		DB  0
+    BLUE_L   		DB  0
+    HIGH_PART  		DW  0   
+    LOW_PART  		DW  0   
+    NUM  			DB  0  
+DATA ENDS
+;the main code
+CODE SEGMENT
+START:
+    MOV  AX, DATA
+    MOV  DS, AX
+    ;the address of the display buffer 
+    MOV  AX, 0B800H
+    MOV  ES, AX
+	;initialize the loop condition
+    MOV  NUM, 0
+    MOV  LOW_PART, 0
+	;loop to print the ASCII table
+OUT_LOOP:
+    MOV  HIGH_PART, 0
+IN_LOOP:
+    CALL CTRL_ROW_COL
+    CALL PRINT
+    ADD  HIGH_PART, 160
+    INC  NUM
+	MOV  AH, 0
+	MOV	 AL, NUM
+    CMP  AL, 0
+	; if NUM is 0, finish the program
+    JE   FINISH
+    MOV  BL, 25
+	; AL/25
+    DIV  BL
+    CMP  AH, 0
+    JNE  IN_LOOP
+    ADD  LOW_PART, 14
+    JMP  OUT_LOOP
+FINISH:
+    MOV  AX, 4C00H
+    INT  21H
+
+;print each item function
+PRINT  PROC
+    MOV  AL, NUM
+    MOV  AH, 12
+    MOV  BX, HIGH_PART
+    MOV  DI, LOW_PART
+    MOV  ES:[BX + DI], AX
+    MOV  AL, GREEN_HIGH
+    MOV  AH, 10
+    MOV  ES:[BX + DI + 2], AX
+    MOV  AL, GREEN_LOW
+    MOV  ES:[BX + DI + 4], AX
+    MOV  AL, ' '
+    MOV  ES:[BX + DI + 12], AX
+    RET
+PRINT  ENDP
+
+;control the row and column information
+;so that the ascii table is printed in 25 lines
+CTRL_ROW_COL  PROC
+    MOV  AL, NUM
+    MOV  AH, 0
+    MOV  BL, 16
+    DIV  BL
+    CMP  AL, 10
+    JB   PART_1
+    ADD  AL, 7
+PART_1:
+	ADD  AL, '0'
+    MOV  GREEN_HIGH, AL
+    CMP  AH, 10
+    JB   PART_2
+    ADD  AH, 7
+PART_2:
+	ADD  AH, '0'
+    MOV  GREEN_LOW, AH
+    MOV  AL, NUM
+    MOV  AH, 0
+	; AL/10
+    MOV  BL, 10
+    DIV  BL
+    ADD  AH, '0'
+    MOV  BLUE_L, AH
+    MOV  AH, 0
+    DIV  BL
+    ADD  AH, '0'
+    MOV  BLUE_M, AH
+    ADD  AL, '0'
+    MOV  BLUE_H, AL
+    RET
+CTRL_ROW_COL  ENDP
+;the main code ends
+	CODE ENDS
+    END  START
+
+
+

汇编语言程序设计基础/Homework/HW02/HW2_3160______.asm

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+.model small
+.386
+.stack 200h
+.data                         
+	num1     dw   0 ;整数1
+	num2     dw   0 ;整数2
+	product  dd   0 ;乘积
+
+	buffer   db  10 ;0ah缓冲区大小
+	k_size   db  ?  ;实际读入字数的格式，中断调用后，自动填入
+	k_buffer db  10 dup(0)  ;键盘输入最多10个字符  
+	asc_arr  db  "0123456789ABCDEF" ;输出数字时，需要的ASC码 
+	    
+.code
+.STARTUP 
+    
+	call get_int
+	mov num1, ax
+	
+	call crlf	
+	call get_int
+	mov num2, ax
+	
+	;扩展到32寄存器,
+	;然后求乘积
+	movzx eax, num1
+	movzx ebx, num2
+	mul ebx	
+	mov product, eax
+	
+	call crlf
+	movzx eax, num1
+	mov ebx, 10
+	call print_int ;显示第2个整数
+	mov dl, '*'
+	call print_char
+	movzx eax, num2
+	mov ebx, 10
+	call print_int ;显示第2个整数
+	
+	mov dl, '='
+	call print_char
+	;显示10进制乘积
+	call crlf
+	mov eax, product
+	mov ebx, 10
+	call print_int
+	;显示16进制乘积
+	call crlf
+	mov eax, product
+	mov ebx, 16
+	call print_int
+	mov dl, 'H'
+	call print_char
+	;显示2进制乘积
+	call crlf
+	mov eax, product
+	call print_bin
+	mov dl, 'B'
+	call print_char
+.EXIT
+
+;eax -整数 
+;ebx -进制
+print_int proc
+
+	mov cx, 0   ;统计整数的位数
+L_div:
+    mov edx, 0  ;除法之前edx清0
+    div ebx 
+    push dx     ;余数入栈
+    inc cx      ;统计位数+1
+    cmp eax, 0  ;eax除尽
+    jne L_div 
+  
+L_print:
+    pop si      ;取出余数
+	mov dl, asc_arr[si]
+	mov ah, 2
+	int 21h
+    loop  L_print
+
+	ret
+print_int endp
+;输入十进制字符串
+;转换二进制,返回值ax	
+get_int proc
+
+	;0ah 键盘读入一个整数字符串
+	lea dx, buffer
+    mov ah,0ah
+	int 21h
+	
+    mov ch,0
+    mov cl, k_size;
+	mov ax, 0 ; 整数初始0
+	lea si, k_buffer
+	
+	mov dh, 0
+	mov bx, 10
+L_read:
+    mul bx  ;乘10
+    mov dl, [si]
+    sub dl, '0'
+    
+	add ax, dx ;ax加上当前的数字
+    inc si    
+    loop L_read 
+
+	ret
+get_int endp
+;输出一个换行
+crlf proc
+	push ax
+	push dx
+	
+	mov dl, 0dh
+	mov ah,2
+	int 21h
+	mov dl,0ah
+	mov ah,2
+	int 21h
+
+	pop dx
+	pop ax	
+	ret
+crlf endp
+;显示一个整数的二进制
+; eax - 整数
+print_bin proc
+	
+	mov cx, 8 ;8组
+L1:
+	push cx
+	mov cx, 4 ;一次显示4位
+L2:	
+	shl eax, 1
+	jc is_1
+	mov dl, '0' ;0
+	call print_char
+	jmp L2_next
+is_1:
+	mov dl, '1' ;1
+	call print_char
+L2_next:
+	loop L2
+
+	mov dl, ' ' ;显示一个空格
+	call print_char
+
+	pop cx
+	loop L1
+
+	mov dl, 8 ;退格
+	call print_char
+	
+	ret
+print_bin endp
+;显示dl里面的字符
+print_char proc
+	push ax
+	mov ah, 2
+	int 21h
+	pop ax
+	ret
+print_char endp
+    end