Typo in stderr message in serialize (libigl#1789)

Something very minor.. but I was searching through the source where the `is not serializable: derive from igl::Serializable or spezialize the template function` message came from by searching for 'specialize'.
jigli · Jul 20, 2021 · dda1972 · dda1972
1 parent 7de3ff0
commit dda1972
Showing 1 changed file with 2 additions and 2 deletions.
diff --git a/include/igl/serialize.h b/include/igl/serialize.h
@@ -1245,13 +1245,13 @@ namespace igl
     template <typename T>
     inline void serialize(const T& obj,std::vector<char>& buffer)
     {
-      std::cerr << typeid(obj).name() << " is not serializable: derive from igl::Serializable or spezialize the template function igl::serialization::serialize(const T& obj,std::vector<char>& buffer)" << std::endl;
+      std::cerr << typeid(obj).name() << " is not serializable: derive from igl::Serializable or specialize the template function igl::serialization::serialize(const T& obj,std::vector<char>& buffer)" << std::endl;
     }
 
     template <typename T>
     inline void deserialize(T& obj,const std::vector<char>& buffer)
     {
-      std::cerr << typeid(obj).name() << " is not deserializable: derive from igl::Serializable or spezialize the template function igl::serialization::deserialize(T& obj, const std::vector<char>& buffer)" << std::endl;
+      std::cerr << typeid(obj).name() << " is not deserializable: derive from igl::Serializable or specialize the template function igl::serialization::deserialize(T& obj, const std::vector<char>& buffer)" << std::endl;
     }
 
     // helper functions