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Update 第一章_数学基础.md
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修改了1.5.2:sigma 应为标准差
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YifeiCN authored Jun 26, 2020
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Expand Up @@ -409,7 +409,7 @@ $$
$$
N(x;\mu,\sigma^2) = \sqrt{\frac{1}{2\pi\sigma^2}}exp\left ( -\frac{1}{2\sigma^2}(x-\mu)^2 \right )
$$
其中, $\mu​$和$\sigma​$分别是均值和方差, 中心峰值x坐标由$\mu​$给出, 峰的宽度受$\sigma​$控制, 最大点在$x=\mu​$处取得, 拐点为$x=\mu\pm\sigma​$
其中, $\mu​$和$\sigma​$分别是均值和标准差, 中心峰值x坐标由$\mu​$给出, 峰的宽度受$\sigma​$控制, 最大点在$x=\mu​$处取得, 拐点为$x=\mu\pm\sigma​$

正态分布中,±1$\sigma$、±2$\sigma$、±3$\sigma$下的概率分别是68.3%、95.5%、99.73%,这3个数最好记住。

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