crypto: padlock-sha - Fix stack alignment

The PadLock hardware requires the output buffer for SHA to be
128-bit aligned.  We currentply place the buffer on the stack,
and ask gcc to align it to 128 bits.  That doesn't work on i386
because the kernel stack is only aligned to 32 bits.  This patch
changes the code to align the buffer by hand so that the hardware
doesn't fault on unaligned buffers.

Reported-by: Séguier Régis <[email protected]>
Tested-by: Séguier Régis <[email protected]>
Signed-off-by: Herbert Xu <[email protected]>

drivers/crypto/padlock-sha.c

@@ -24,6 +24,12 @@
 #include <asm/i387.h>
 #include "padlock.h"
 
+#ifdef CONFIG_64BIT
+#define STACK_ALIGN 16
+#else
+#define STACK_ALIGN 4
+#endif
+
 struct padlock_sha_desc {
 	struct shash_desc fallback;
 };
@@ -64,7 +70,9 @@ static int padlock_sha1_finup(struct shash_desc *desc, const u8 *in,
 	/* We can't store directly to *out as it may be unaligned. */
 	/* BTW Don't reduce the buffer size below 128 Bytes!
 	 *     PadLock microcode needs it that big. */
-	char result[128] __attribute__ ((aligned(PADLOCK_ALIGNMENT)));
+	char buf[128 + PADLOCK_ALIGNMENT - STACK_ALIGN] __attribute__
+		((aligned(STACK_ALIGN)));
+	char *result = PTR_ALIGN(&buf[0], PADLOCK_ALIGNMENT);
 	struct padlock_sha_desc *dctx = shash_desc_ctx(desc);
 	struct sha1_state state;
 	unsigned int space;
@@ -128,7 +136,9 @@ static int padlock_sha256_finup(struct shash_desc *desc, const u8 *in,
 	/* We can't store directly to *out as it may be unaligned. */
 	/* BTW Don't reduce the buffer size below 128 Bytes!
 	 *     PadLock microcode needs it that big. */
-	char result[128] __attribute__ ((aligned(PADLOCK_ALIGNMENT)));
+	char buf[128 + PADLOCK_ALIGNMENT - STACK_ALIGN] __attribute__
+		((aligned(STACK_ALIGN)));
+	char *result = PTR_ALIGN(&buf[0], PADLOCK_ALIGNMENT);
 	struct padlock_sha_desc *dctx = shash_desc_ctx(desc);
 	struct sha256_state state;
 	unsigned int space;