forked from TheAlgorithms/Python
-
Notifications
You must be signed in to change notification settings - Fork 0
Commit
This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository.
Added solution for Project Euler problem 125 (TheAlgorithms#3073)
* Added solution for Project Euler problem 125 * Fixed typos
- Loading branch information
Showing
2 changed files
with
56 additions
and
0 deletions.
There are no files selected for viewing
Empty file.
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,56 @@ | ||
""" | ||
Problem 125: https://projecteuler.net/problem=125 | ||
The palindromic number 595 is interesting because it can be written as the sum | ||
of consecutive squares: 6^2 + 7^2 + 8^2 + 9^2 + 10^2 + 11^2 + 12^2. | ||
There are exactly eleven palindromes below one-thousand that can be written as | ||
consecutive square sums, and the sum of these palindromes is 4164. Note that | ||
1 = 0^2 + 1^2 has not been included as this problem is concerned with the | ||
squares of positive integers. | ||
Find the sum of all the numbers less than 10^8 that are both palindromic and can | ||
be written as the sum of consecutive squares. | ||
""" | ||
|
||
|
||
def is_palindrome(n: int) -> bool: | ||
""" | ||
Check if an integer is palindromic. | ||
>>> is_palindrome(12521) | ||
True | ||
>>> is_palindrome(12522) | ||
False | ||
>>> is_palindrome(12210) | ||
False | ||
""" | ||
if n % 10 == 0: | ||
return False | ||
s = str(n) | ||
return s == s[::-1] | ||
|
||
|
||
def solution() -> int: | ||
""" | ||
Returns the sum of all numbers less than 1e8 that are both palindromic and | ||
can be written as the sum of consecutive squares. | ||
""" | ||
LIMIT = 10 ** 8 | ||
answer = set() | ||
first_square = 1 | ||
sum_squares = 5 | ||
while sum_squares < LIMIT: | ||
last_square = first_square + 1 | ||
while sum_squares < LIMIT: | ||
if is_palindrome(sum_squares): | ||
answer.add(sum_squares) | ||
last_square += 1 | ||
sum_squares += last_square ** 2 | ||
first_square += 1 | ||
sum_squares = first_square ** 2 + (first_square + 1) ** 2 | ||
|
||
return sum(answer) | ||
|
||
|
||
if __name__ == "__main__": | ||
print(solution()) |