Skip to content

Commit

Permalink
First Update
Browse files Browse the repository at this point in the history
  • Loading branch information
huihut committed Feb 9, 2018
0 parents commit 6b742a5
Show file tree
Hide file tree
Showing 11 changed files with 298 additions and 0 deletions.
9 changes: 9 additions & 0 deletions .vscode/settings.json
Original file line number Diff line number Diff line change
@@ -0,0 +1,9 @@
{
"files.associations": {
"initializer_list": "cpp",
"type_traits": "cpp",
"xstring": "cpp",
"xtree": "cpp",
"xutility": "cpp"
}
}
14 changes: 14 additions & 0 deletions Algorithm/BubbleSort.h
Original file line number Diff line number Diff line change
@@ -0,0 +1,14 @@
// 冒泡排序

void BubbleSort(vector<int>& v) {
int temp;
for (int i = 0; i < v.size() - 1; ++i) {
for (int j = 0; j < v.size() - 1 - i; ++j) {
if (v[j] > v[j + 1]) { // 从小到大
temp = v[j];
v[j] = v[j + 1];
v[j + 1] = temp;
}
}
}
}
18 changes: 18 additions & 0 deletions Algorithm/BubbleSort_orderly.h
Original file line number Diff line number Diff line change
@@ -0,0 +1,18 @@
// 冒泡排序(跳过有序的改进版)

void BubbleSort_orderly(vector<int>& v) {
int temp;
bool orderly = false;
for (int i = 0; i < v.size() - 1 && !orderly; ++i) {
orderly = true;
for (int j = 0; j < v.size() - 1 - i; ++j) {
if (v[j] > v[j + 1])
{
orderly = false;
temp = v[j];
v[j] = v[j + 1];
v[j + 1] = temp;
}
}
}
}
14 changes: 14 additions & 0 deletions Problems/LeetcodeProblems/best-time-to-buy-and-sell-stock.h
Original file line number Diff line number Diff line change
@@ -0,0 +1,14 @@
class Solution {
public:
int maxProfit(vector<int>& prices) {
int left = 0, right = 0;
int max = 0, temp = 0;
for(auto i = 0; i < prices.size(); ++i) {
right = i;
temp = prices[right] - prices[left];
if(temp < 0) left = i;
if(max < temp) max = temp;
}
return max;
}
};
22 changes: 22 additions & 0 deletions Problems/LeetcodeProblems/container-with-most-water.h
Original file line number Diff line number Diff line change
@@ -0,0 +1,22 @@
class Solution {
public:
int maxArea(vector<int>& height) {
int left = 0, right = height.size()-1;
int max = 0, temp = 0;
while(left < right) {
temp = (right - left) * (height[left] < height[right] ? height[left] : height[right]);
if(max < temp) max = temp;
if(height[left] < height[right]) {
do{
left++;
} while(left < right && height[left-1] >= height[left]);
}
else {
do{
right--;
} while(left < right && height[right] <= height[right+1]);
}
}
return max;
}
};
26 changes: 26 additions & 0 deletions Problems/LeetcodeProblems/majority-element.h
Original file line number Diff line number Diff line change
@@ -0,0 +1,26 @@
#include <map>
class Solution {
public:
int majorityElement(vector<int>& nums) {
int n = nums.size();
map<int, int> m_times;
int moreThanTimes = n / 2;
for (auto i = 0; i < n; ++i) {
auto it = m_times.find(nums[i]);
if (it == m_times.end()) {
// No existence in map, insert
m_times.insert(std::pair<int, int>(nums[i], 1));
it = m_times.find(nums[i]);
}
// Is it more than ⌊ n/2 ⌋ times ?
if ((*it).second > moreThanTimes) {
return (*it).first;
}
else {
(*it).second++;
}
}
// Can't find
return -1;
}
};
13 changes: 13 additions & 0 deletions Problems/LeetcodeProblems/maximum-subarray.h
Original file line number Diff line number Diff line change
@@ -0,0 +1,13 @@
#define MIN_INT -2147483648
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int max = MIN_INT, temp = 0;
for(auto i = 0; i < nums.size(); ++i) {
temp += nums[i];
if(temp > max) max = temp;
if(temp < 0) temp = 0;
}
return max;
}
};
Empty file.
12 changes: 12 additions & 0 deletions Problems/LeetcodeProblems/move-zeroes.h
Original file line number Diff line number Diff line change
@@ -0,0 +1,12 @@
class Solution {
public:
void moveZeroes(vector<int>& nums) {
int left = 0, right = 0;
for(; left < nums.size() && nums[left] != 0; left++);
for(right = left; right < nums.size(); right++) {
if(nums[right] == 0) continue;
nums[left++] = nums[right];
}
while(left < nums.size()) nums[left++] = 0;
}
};
18 changes: 18 additions & 0 deletions Problems/LeetcodeProblems/two-sum.h
Original file line number Diff line number Diff line change
@@ -0,0 +1,18 @@
class Solution {
public:
vector<int> twoSum(vector<int>& nums, int target) {
vector<int> sum;
for(auto i = 0; i < nums.size(); i++)
{
for(auto j = i+1; j < nums.size(); j++)
{
if(i == j) continue;
if(nums[i] + nums[j] != target) continue;
sum.push_back(i);
sum.push_back(j);
return sum;
}
}
return sum;
}
};
152 changes: 152 additions & 0 deletions README.md
Original file line number Diff line number Diff line change
@@ -0,0 +1,152 @@

## 目录

* [C/C++](#)
* [STL](#)
* [数据结构](#)
* [算法](#)
* [Problems](#)
* [操作系统](#)
* [计算机网络](#)
* [数据库](#)
* [设计模式](#)
* [网络编程](#)
* [海量数据处理](#)
* [其他](#)
* [书籍](#)
* [复习刷题网站](##)
* [面试题目经验](##)

----

## C/C++

* 封装
* 继承
* 多态
* 虚函数
* 内存分配和管理
* extern"C"
* const作用
* 什么是面向对象(OOP)
* new和malloc的区别
* 运行时类型识别(RTTI)
* 友元类和友元函数
* struct和class的区别

## STL

## 数据结构

## 算法

### 排序

* [冒泡排序](Algorithm/BubbleSort.h)
* [冒泡排序(跳过有序的改进版)](Algorithm/BubbleSort_orderly.h)

## Problems

### Leetcode Problems

#### Array

* [1. Two Sum](Problems/LeetcodeProblems/two-sum.h)
* [4. Median of Two Sorted Arrays](Problems/LeetcodeProblems/median-of-two-sorted-arrays.h)
* [11. Container With Most Water](Problems/LeetcodeProblems/container-with-most-water.h)
* [53. Maximum Subarray](Problems/LeetcodeProblems/maximum-subarray.h)
* [121. Best Time to Buy and Sell Stock](Problems/LeetcodeProblems/best-time-to-buy-and-sell-stock.h)
* [169. Majority Element](Problems/LeetcodeProblems/majority-element.h)
* [283. Move Zeroes](Problems/LeetcodeProblems/move-zeroes.h)


## 操作系统

* 进程间的通信方式(管道、有名管道、信号、共享内存、消息队列、信号量、套接字、文件)

## 计算机网络

* TCP/IP
* TCP协议
* TCP三次握手
* TCP和UDP的区别
* socket套接字
* HTTP返回码

### HTTP

[runoob . HTTP教程](http://www.runoob.com/http/http-tutorial.html)

#### HTTP 请求方法
* GET:请求指定的页面信息,并返回实体主体
* HEAD:类似于get请求,只不过返回的响应中没有具体的内容,用于获取报头
* POST:向指定资源提交数据进行处理请求(例如提交表单或者上传文件)。数据被包含在请求体中。POST请求可能会导致新的资源的建立和/或已有资源的修改。
* PUT:从客户端向服务器传送的数据取代指定的文档的内容。
* DELETE:请求服务器删除指定的页面
* CONNECT:HTTP/1.1协议中预留给能够将连接改为管道方式的代理服务器
* OPTIONS:允许客户端查看服务器的性能
* TRACE:回显服务器收到的请求,主要用于测试或诊断

#### HTTP 状态码
* 200 OK: 请求成功
* 301 Moved Permanently: 永久移动。请求的资源已被永久的移动到新URI,返回信息会包括新的URI,浏览器会自动定向到新URI。今后任何新的请求都应使用新的URI代替
* 400 Bad Request: 客户端请求的语法错误,服务器无法理解
* 401 Unauthorized: 请求要求用户的身份认证
* 403 Forbidden: 服务器理解请求客户端的请求,但是拒绝执行此请求
* 404 Not Found: 服务器无法根据客户端的请求找到资源(网页)。通过此代码,网站设计人员可设置"您所请求的资源无法找到"的个性页面
* 408 Request Timeout: 服务器等待客户端发送的请求时间过长,超时
* 500 Internal Server Error: 服务器内部错误,无法完成请求
* 503 Service Unavailable: 由于超载或系统维护,服务器暂时的无法处理客户端的请求。延时的长度可包含在服务器的Retry-After头信息中
* 504 Gateway Timeout: 充当网关或代理的服务器,未及时从远端服务器获取请求

## 数据库

* 数据库事务四大特性:原子性、一致性、分离性、持久性
* 数据库索引:顺序索引 B+树索引 hash索引
[MySQL索引背后的数据结构及算法原理](http://blog.codinglabs.org/articles/theory-of-mysql-index.html)

## 设计模式

## 网络编程

## 海量数据处理

* [ 海量数据处理面试题集锦](http://blog.csdn.net/v_july_v/article/details/6685962)
* [十道海量数据处理面试题与十个方法大总结](http://blog.csdn.net/v_JULY_v/article/details/6279498)

## 其他

----

## 书籍

* 《剑指Offer》
* 《编程珠玑》
* 《深度探索C++对象模型》
* 《Effective C++》
* 《More Effective C++》
* 《深入理解C++11》
* 《STL源码剖析》
* 《深入理解计算机系统》
* 《TCP/IP网络编程》
* 《程序员的自我修养》

## 复习刷题网站

* [leetcode](https://leetcode.com/)
* [牛客网](https://www.nowcoder.net/)
* [慕课网](https://www.imooc.com/)
* [菜鸟教程](http://www.runoob.com/)

## 面试题目经验

* [知乎 . 互联网公司最常见的面试算法题有哪些?](https://www.zhihu.com/question/24964987)
* [知乎 . 面试 C++ 程序员,什么样的问题是好问题?](https://www.zhihu.com/question/20184857)
* [cnblogs . C++面试集锦( 面试被问到的问题 )](https://www.cnblogs.com/Y1Focus/p/6707121.html)
* [cnblogs . C/C++ 笔试、面试题目大汇总](https://www.cnblogs.com/fangyukuan/archive/2010/09/18/1829871.html)
* [cnblogs . 常见C++面试题及基本知识点总结(一)](https://www.cnblogs.com/LUO77/p/5771237.html)
* [CSDN . 全面整理的C++面试题](http://blog.csdn.net/ljzcome/article/details/574158)
* [CSDN . 百度研发类面试题(C++方向)](http://blog.csdn.net/Xiongchao99/article/details/74524807?locationNum=6&fps=1)
* [CSDN . c++常见面试题30道](http://blog.csdn.net/fakine/article/details/51321544)
* [CSDN . 腾讯2016实习生面试经验(已经拿到offer)](http://blog.csdn.net/onever_say_love/article/details/51223886)
* [segmentfault . C++常见面试问题总结](https://segmentfault.com/a/1190000003745529)

0 comments on commit 6b742a5

Please sign in to comment.