crypto: gf128mul - fix call to memset()

In gf128mul_lle() and gf128mul_bbe() r isn't completely initialized with zero because the size argument passed to memset() is the size of the pointer, not the structure it points to. Luckily there are no in-kernel users of those functions so the ABI change implied by this fix should break no existing code. Based on a patch by the PaX Team. Signed-off-by: Mathias Krause <[email protected]> Cc: PaX Team <[email protected]> Acked-by: David S. Miller <[email protected]> Signed-off-by: Herbert Xu <[email protected]>
niw · Jul 8, 2011 · 6254266 · 6254266
1 parent e3b4f51
commit 6254266
Showing 1 changed file with 2 additions and 2 deletions.
diff --git a/crypto/gf128mul.c b/crypto/gf128mul.c
@@ -182,7 +182,7 @@ void gf128mul_lle(be128 *r, const be128 *b)
 	for (i = 0; i < 7; ++i)
 		gf128mul_x_lle(&p[i + 1], &p[i]);
 
-	memset(r, 0, sizeof(r));
+	memset(r, 0, sizeof(*r));
 	for (i = 0;;) {
 		u8 ch = ((u8 *)b)[15 - i];
 
@@ -220,7 +220,7 @@ void gf128mul_bbe(be128 *r, const be128 *b)
 	for (i = 0; i < 7; ++i)
 		gf128mul_x_bbe(&p[i + 1], &p[i]);
 
-	memset(r, 0, sizeof(r));
+	memset(r, 0, sizeof(*r));
 	for (i = 0;;) {
 		u8 ch = ((u8 *)b)[i];