Watch directory and execute

for each new file in the watched directory, execute given command

how to?

• Download and install python 3
• Execute: pip3 install watchdog
• Execute: python3 main.py --help

expected result

r-santos@rafmbp ~/d/p/watchnexecute-python> python3 main.py --help                                           
usage: main.py [-h] dir cmd

Watch directory and execute cmd.

positional arguments:
  dir         directory to watch
  cmd         cmd to be executued for each new file

optional arguments:
  -h, --help  show this help message and exit

Usage example #1

start: 
python3 main.py ./ "cat %s | grep thingy"

output: 
watching directory: "./"
will execute "cat %s | grep thingy" for directory modified files.

input: 
touch example.test

output: 
executing "cat ./example.test | grep thingy"

input:
echo "thingy" >> example.test 

output: 
executing "cat ./example.test | grep thingy"
thingy

Usage example #2

open new file in text editor MacOS

r-santos@rafmbp ~/d/p/watchnexecute-python> python3 main.py ./ "open -a Visual\ Studio\ Code %s"

watching directory "./"

will execute "open -a open -a Visual\ Studio\ Code %s" for directory modified files.

Visual studio code should pop up with the modified or created file.

If the file is deleted the cmd will throw an error, telling visual studio couldn't find the file.