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io_uring: include task_work run after scheduling in wait for events
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It's quite possible that we got woken up because task_work was queued,
and we need to process this task_work to generate the events waited for.
If we return to the wait loop without running task_work, we'll end up
adding the task to the waitqueue again, only to call
io_cqring_wait_schedule() again which will run the task_work. This is
less efficient than it could be, as it requires adding to the cq_wait
queue again. It also triggers the wakeup path for completions as
cq_wait is now non-empty with the task itself, and it'll require another
lock grab and deletion to remove ourselves from the waitqueue.

Signed-off-by: Jens Axboe <[email protected]>
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axboe committed Dec 18, 2022
1 parent 6434ec0 commit 35d90f9
Showing 1 changed file with 10 additions and 1 deletion.
11 changes: 10 additions & 1 deletion io_uring/io_uring.c
Original file line number Diff line number Diff line change
Expand Up @@ -2481,7 +2481,14 @@ static inline int io_cqring_wait_schedule(struct io_ring_ctx *ctx,
}
if (!schedule_hrtimeout(&timeout, HRTIMER_MODE_ABS))
return -ETIME;
return 1;

/*
* Run task_work after scheduling. If we got woken because of
* task_work being processed, run it now rather than let the caller
* do another wait loop.
*/
ret = io_run_task_work_sig(ctx);
return ret < 0 ? ret : 1;
}

/*
Expand Down Expand Up @@ -2546,6 +2553,8 @@ static int io_cqring_wait(struct io_ring_ctx *ctx, int min_events,
prepare_to_wait_exclusive(&ctx->cq_wait, &iowq.wq,
TASK_INTERRUPTIBLE);
ret = io_cqring_wait_schedule(ctx, &iowq, timeout);
if (__io_cqring_events_user(ctx) >= min_events)
break;
cond_resched();
} while (ret > 0);

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