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type-challenges#5423 - Intersection (type-challenges#5424)
Co-authored-by: Pineapple <[email protected]>
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Implement the type version of Lodash.intersection, but there is a little different, Intersection<T> takes an Array T containing several arrays or any type element that includes the union type, returns a new array containing all incoming array intersection elements. | ||
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```ts | ||
type Res = Intersection<[[1, 2], [2, 3], [2, 2]]>; // expected to be 2 | ||
type Res1 = Intersection<[[1, 2, 3], [2, 3, 4], [2, 2, 3]]>; // expected to be 2 | 3 | ||
type Res2 = Intersection<[[1, 2], [3, 4], [5, 6]]>; // expected to be never | ||
type Res3 = Intersection<[[1, 2, 3], [2, 3, 4], 3]>; // expected to be 3 | ||
type Res4 = Intersection<[[1, 2, 3], 2 | 3 | 4, 2 | 3]>; // expected to be 2 | 3 | ||
type Res5 = Intersection<[[1, 2, 3], 2, 3]>; // expected to be never | ||
``` |
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difficulty: hard | ||
title: Intersection | ||
tags: union, array | ||
author: | ||
github: Pineapple0919 | ||
name: Pineapple | ||
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type Intersection<T> = any |
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import { Equal, Expect } from '@type-challenges/utils' | ||
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type cases = [ | ||
Expect<Equal<Intersection<[[1, 2], [2, 3], [2, 2]]>, 2>>, | ||
Expect<Equal<Intersection<[[1, 2, 3], [2, 3, 4], [2, 2, 3]]>, 2 | 3>>, | ||
Expect<Equal<Intersection<[[1, 2], [3, 4], [5, 6]]>, never>>, | ||
Expect<Equal<Intersection<[[1, 2, 3], [2, 3, 4], 3]>, 3>>, | ||
Expect<Equal<Intersection<[[1, 2, 3], 2 | 3 | 4, 2 | 3]>, 2 | 3>>, | ||
Expect<Equal<Intersection<[[1, 2, 3], 2, 3]>, never>> | ||
] |