forked from YuriSpiridonov/LeetCode
-
Notifications
You must be signed in to change notification settings - Fork 0
Commit
This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository.
1047. Remove All Adjacent Duplicates In String
Difficulty: Easy 98 / 98 test cases passed. Runtime: 128 ms Memory Usage: 13.7 MB
- Loading branch information
1 parent
12bbc57
commit 01cbcc3
Showing
1 changed file
with
40 additions
and
0 deletions.
There are no files selected for viewing
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,40 @@ | ||
""" | ||
Given a string S of lowercase letters, a duplicate removal consists of | ||
choosing two adjacent and equal letters, and removing them. | ||
We repeatedly make duplicate removals on S until we no longer can. | ||
Return the final string after all such duplicate removals have been made. | ||
It is guaranteed the answer is unique. | ||
Example: | ||
Input: "abbaca" | ||
Output: "ca" | ||
Explanation: | ||
For example, in "abbaca" we could remove "bb" since the letters are | ||
adjacent and equal, and this is the only possible move. The result of this | ||
move is that the string is "aaca", of which only "aa" is possible, so the | ||
final string is "ca". | ||
Note: | ||
1. 1 <= S.length <= 20000 | ||
2. S consists only of English lowercase letters. | ||
""" | ||
#Difficulty: Easy | ||
#98 / 98 test cases passed. | ||
#Runtime: 128 ms | ||
#Memory Usage: 13.7 MB | ||
|
||
#Runtime: 128 ms, faster than 25.09% of Python3 online submissions for Remove All Adjacent Duplicates In String. | ||
#Memory Usage: 13.7 MB, less than 98.64% of Python3 online submissions for Remove All Adjacent Duplicates In String. | ||
|
||
class Solution: | ||
def removeDuplicates(self, S: str) -> str: | ||
i = 0 | ||
while True: | ||
if i + 1 > len(S) - 1: | ||
break | ||
if S[i] == S[i+1]: | ||
S = S[:i] + S[i+2:] | ||
i = max(i-1, 0) | ||
else: | ||
i += 1 | ||
return S |