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''' | ||
You have an array arr of length n where arr[i] = (2 * i) + 1 | ||
for all valid values of i (i.e. 0 <= i < n). | ||
In one operation, you can select two indices x and y | ||
where 0 <= x, y < n and subtract 1 from arr[x] and add | ||
1 to arr[y] (i.e. perform arr[x] -=1 and arr[y] += 1). | ||
The goal is to make all the elements of the array equal. | ||
It is guaranteed that all the elements of the array can | ||
be made equal using some operations. | ||
Given an integer n, the length of the array. Return the | ||
minimum number of operations needed to make all the | ||
elements of arr equal. | ||
Example: | ||
Input: n = 3 | ||
Output: 2 | ||
Explanation: arr = [1, 3, 5] | ||
First operation choose x = 2 and y = 0, | ||
this leads arr to be [2, 3, 4] | ||
In the second operation choose x = 2 and | ||
y = 0 again, thus arr = [3, 3, 3]. | ||
Example: | ||
Input: n = 6 | ||
Output: 9 | ||
Constraints: | ||
- 1 <= n <= 10^4 | ||
''' | ||
#Difficulty: Medium | ||
#301 / 301 test cases passed. | ||
#Runtime: 76 ms | ||
#Memory Usage: 14.3 MB | ||
|
||
#Runtime: 76 ms, faster than 38.50% of Python3 online submissions for Minimum Operations to Make Array Equal. | ||
#Memory Usage: 14.3 MB, less than 50.38% of Python3 online submissions for Minimum Operations to Make Array Equal. | ||
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||
class Solution: | ||
def minOperations(self, n: int) -> int: | ||
x = (2 + 2*(n-1)) // 2 | ||
y = 0 | ||
for i in range(n//2): | ||
y += x - (i*2+1) | ||
return y |
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