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Update longest common subsequence.py
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Mayank Kumar Jha authored Aug 30, 2017
1 parent 0e857d8 commit aae1562
Showing 1 changed file with 41 additions and 11 deletions.
52 changes: 41 additions & 11 deletions dynamic_programming/longest common subsequence.py
Original file line number Diff line number Diff line change
Expand Up @@ -3,16 +3,46 @@
A subsequence is a sequence that appears in the same relative order, but not necessarily continious.
Example:"abc", "abg" are subsequences of "abcdefgh".
"""
def LCS(s1, s2):
m = len(s1)
n = len(s2)
def LCS(x,y):
b=[[] for j in range(len(x)+1)]
c=[[] for i in range(len(x))]
for i in range(len(x)+1):
b[i].append(0)
for i in range(1,len(y)+1):
b[0].append(0)
for i in range(len(x)):
for j in range(len(y)):
if x[i]==y[j]:
b[i+1].append(b[i][j]+1)
c[i].append('/')
elif b[i][j+1]>=b[i+1][j]:
b[i+1].append(b[i][j+1])
c[i].append('|')
else :
b[i+1].append(b[i+1][j])
c[i].append('-')
return b,c

arr = [[0 for i in range(n+1)]for j in range(m+1)]

for i in range(1,m+1):
for j in range(1,n+1):
if s1[i-1] == s2[j-1]:
arr[i][j] = arr[i-1][j-1]+1
else:
arr[i][j] = max(arr[i-1][j], arr[i][j-1])
return arr[m][n]
def print_lcs(x,c,n,m):
n,m=n-1,m-1
ans=[]
while n>=0 and m>=0:
if c[n][m]=='/':
ans.append(x[n])
n,m=n-1,m-1
elif c[n][m]=='|':
n=n-1
else:
m=m-1
ans=ans[::-1]
return ans


if __name__=='__main__':
x=['a','b','c','b','d','a','b']
y=['b','d','c','a','b','a']
b,c=LCS(x,y)
print('Given \nX : ',x)
print('Y : ',y)
print('LCS : ',print_lcs(x,c,len(x),len(y)))

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