feat: add Swift codes for space time tradeoff article

codes/swift/Package.swift

@@ -8,11 +8,13 @@ let package = Package(
         .executable(name: "time_complexity", targets: ["time_complexity"]),
         .executable(name: "worst_best_time_complexity", targets: ["worst_best_time_complexity"]),
         .executable(name: "space_complexity", targets: ["space_complexity"]),
+        .executable(name: "leetcode_two_sum", targets: ["leetcode_two_sum"]),
     ],
     targets: [
         .target(name: "utils", path: "utils"),
         .executableTarget(name: "time_complexity", path: "chapter_computational_complexity", sources: ["time_complexity.swift"]),
         .executableTarget(name: "worst_best_time_complexity", path: "chapter_computational_complexity", sources: ["worst_best_time_complexity.swift"]),
         .executableTarget(name: "space_complexity", dependencies: ["utils"], path: "chapter_computational_complexity", sources: ["space_complexity.swift"]),
+        .executableTarget(name: "leetcode_two_sum", path: "chapter_computational_complexity", sources: ["leetcode_two_sum.swift"]),
     ]
 )

codes/swift/chapter_computational_complexity/leetcode_two_sum.swift

@@ -0,0 +1,46 @@
+/*
+ * File: leetcode_two_sum.swift
+ * Created Time: 2023-01-03
+ * Author: nuomi1 ([email protected])
+ */
+
+func twoSumBruteForce(nums: [Int], target: Int) -> [Int] {
+    // 两层循环，时间复杂度 O(n^2)
+    for i in nums.indices.dropLast() {
+        for j in nums.indices.dropFirst(i + 1) {
+            if nums[i] + nums[j] == target {
+                return [i, j]
+            }
+        }
+    }
+    return [0]
+}
+
+func twoSumHashTable(nums: [Int], target: Int) -> [Int] {
+    // 辅助哈希表，空间复杂度 O(n)
+    var dic: [Int: Int] = [:]
+    // 单层循环，时间复杂度 O(n)
+    for i in nums.indices {
+        if let j = dic[target - nums[i]] {
+            return [j, i]
+        }
+        dic[nums[i]] = i
+    }
+    return [0]
+}
+
+@main
+enum LeetcodeTwoSum {
+    static func main() {
+        // ======= Test Case =======
+        let nums = [2, 7, 11, 15]
+        let target = 9
+        // ====== Driver Code ======
+        // 方法一
+        var res = twoSumBruteForce(nums: nums, target: target)
+        print("方法一 res = \(res)")
+        // 方法二
+        res = twoSumHashTable(nums: nums, target: target)
+        print("方法二 res = \(res)")
+    }
+}

docs/chapter_computational_complexity/space_time_tradeoff.md

@@ -149,6 +149,22 @@ comments: true
     }
     ```
 
+=== "Swift"
+
+    ```swift title="leetcode_two_sum.swift"
+    func twoSumBruteForce(nums: [Int], target: Int) -> [Int] {
+        // 两层循环，时间复杂度 O(n^2)
+        for i in nums.indices.dropLast() {
+            for j in nums.indices.dropFirst(i + 1) {
+                if nums[i] + nums[j] == target {
+                    return [i, j]
+                }
+            }
+        }
+        return [0]
+    }
+    ```
+
 ### 方法二：辅助哈希表
 
 时间复杂度 $O(N)$ ，空间复杂度 $O(N)$ ，属于「空间换时间」。
@@ -294,3 +310,20 @@ comments: true
         }
     }
     ```
+
+=== "Swift"
+
+    ```swift title="leetcode_two_sum.swift"
+    func twoSumHashTable(nums: [Int], target: Int) -> [Int] {
+        // 辅助哈希表，空间复杂度 O(n)
+        var dic: [Int: Int] = [:]
+        // 单层循环，时间复杂度 O(n)
+        for i in nums.indices {
+            if let j = dic[target - nums[i]] {
+                return [j, i]
+            }
+            dic[nums[i]] = i
+        }
+        return [0]
+    }
+    ```