Create 1873. Calculate Special Bonus

1873. Calculate Special Bonus

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+
+Table: Employees
+
++-------------+---------+
+| Column Name | Type    |
++-------------+---------+
+| employee_id | int     |
+| name        | varchar |
+| salary      | int     |
++-------------+---------+
+employee_id is the primary key (column with unique values) for this table.
+Each row of this table indicates the employee ID, employee name, and salary.
+
+
+Write a solution to calculate the bonus of each employee. The bonus of an employee is 100% of their salary if the ID of the employee is an odd number and the employee's name does not start with the character 'M'. The bonus of an employee is 0 otherwise.
+
+Return the result table ordered by employee_id.
+
+The result format is in the following example.
+
+
+
+Example 1:
+
+Input: 
+Employees table:
++-------------+---------+--------+
+| employee_id | name    | salary |
++-------------+---------+--------+
+| 2           | Meir    | 3000   |
+| 3           | Michael | 3800   |
+| 7           | Addilyn | 7400   |
+| 8           | Juan    | 6100   |
+| 9           | Kannon  | 7700   |
++-------------+---------+--------+
+Output: 
++-------------+-------+
+| employee_id | bonus |
++-------------+-------+
+| 2           | 0     |
+| 3           | 0     |
+| 7           | 7400  |
+| 8           | 0     |
+| 9           | 7700  |
++-------------+-------+
+Explanation: 
+The employees with IDs 2 and 8 get 0 bonus because they have an even employee_id.
+The employee with ID 3 gets 0 bonus because their name starts with 'M'.
+The rest of the employees get a 100% bonus.
+-------------------------------------
+# Write your MySQL query statement below
+select employee_id ,case when employee_id %2<>0 and lower(name) not like 'm%' then  salary else 0 end as BONUS
+
+from Employees